The ratio of mole number of the reactants and products is equal to the coefficients. So the answer is a. 18.75 mol. b. 35.1 g. c. 1.38 * 10^5 g.
Answer:
The enthalpy of the reaction is –184.6 kJ, and the reaction is exothermic.
Explanation:
Subtract 275.15° from any Kevin temperature.
Answer:
sodium fluoride
Explanation:
When we add sodium fluoride to a solution of a given mixture, we get barium fluoride from Ba, which would be an insoluble salt, and silver fluoride from Ag, which would be a soluble salt.
The solubility rule will be used to determine the barium salt that forms as a precipitate and leaves Ag+ salt in the solution.
From the following equations, we will see that the precipitate is formed in Ba but Ag remains dissolved in the solution.


Answer:
+375.2 KJ.
Explanation:
The balanced equation for the reaction is given below:
H₂ + F₂ —> 2HF ΔH = +536 KJ
From the balanced equation above,
2 moles of HF required +536 KJ .
Finally, we shall determine the heat required to produce 1.4 mol of hydrogen fluoride, HF. This is illustrated below:
From the balanced equation above,
2 moles of HF required +536 KJ .
Therefore, 1.4 moles of HF will require = (1.4 × 536)/2 = +375.2 KJ
Thus, +375.2 KJ of heat energy is required.