Explanation:
Mg(s) + Cr(C2H3O2)3 (aq)
Overall, balanced molecular equation
Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)
To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.
An increase in oxidation number denotes that the element has been oxidized.
A decrease in oxidation number denotes that the element has been reduced.
Oxidation number of Mg:
Reactant - 0
Product - +3
Oxidation number of Cr:
Reactant - +3
Product - 0
Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.
Oxidized : Mg
Reduced : Cr
Explanation:
Aluminium is Al on the periodic table.
But is this the complete question
Explanation:
hindi ko po alam kong tama yan
Answer:
a) [HA] = 0.012 M; [A-] = 4 E-3 M
b) pH = 3.47
Explanation:
neutralization reaction:
∴ mol HA = 0.0015 mol
∴ mol A- = 0.0005 mol
∴ Vsln = 125 mL = 0.125 L
a) approx. concentration:
⇒ [HA] = 0.0015 mol / 0.125 L = 0.012 mol/L
⇒ [A-] = 0.0005 mol / 0.125 L = 4 E-3 mol/L
b) pH = ?
∴ pKa = 3.90 = - Log Ka
⇒ Ka = 1.26 E-4 = ([H3O+]*( 4 E-3 + [H3O+])) / (0.012 - [H3O+])
⇒ 1.512 E-6 - 1.26 E-4[H3O+] = 4 E-3[H3O+] + [H3O+]²
⇒ [H3O+]² + 4.126 E-3[H3O+] - 1.512 E-6 = 0
⇒ [H3O+] = 3.3866 E-4 M
⇒ pH = 3.4702
