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AysviL [449]
3 years ago
9

What are the square roots of 36100?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0

\huge\text{Hey there!}

\large\textsf{What are \bf the square roots of 36,100?}

\mathsf{\sqrt{36,100}=190\times190 = \bold{190}^2}

\mathsf{190^2=36,100}

\mathsf{(- 190)^2=36,100}

\mathsf{190\times190=36,100}

\mathsf{\sqrt{36,100}=\bf 190}

\mathsf{-\sqrt{36,100}=\bf -190}

\boxed{\boxed{\large\text{Answer: \huge \bf -190 and 190}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

Elina [12.6K]3 years ago
8 0
Use socratic or photomath
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I don’t know how to solve this. Help plz
castortr0y [4]

for every three bottles circle two, it would add up to 12 bottles, so it would be the one on the bottom right

7 0
3 years ago
The graph of y > 1 2 x - 2 is shown. Which set contains only points that satisfy the inequality? A) {(6, 1), (-1, -3), (4, 4)
Kaylis [27]

Answer:

Option B) {(1, -1), (-3, -3), (2, 4)}

Step-by-step explanation:

<u><em>The correct inequality is </em></u>

y>\frac{1}{2}x-2

The solution of the inequality is the shaded area above the dashed line y=\frac{1}{2}x-2

see the attached figure to better understand the problem

we know that

If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution

<u><em>Verify each case</em></u>

case A) {(6, 1), (-1, -3), (4, 4)}

ordered pair (6,1)

For x=6, y=1

substitute in the inequality

1>\frac{1}{2}(6)-2

1>1 ---> is not true

therefore

The point not satisfy the inequality

case B)  {(1, -1), (-3, -3), (2, 4)}

ordered pair (1,-1)

For x=1, y=-1

substitute in the inequality

-1>\frac{1}{2}(1)-2

-1>-1.5 ---> is true

so

The point satisfy the inequality

ordered pair (-3,3)

For x=-3, y=3

substitute in the inequality

3>\frac{1}{2}(-3)-2

3>-3.5 ---> is true

so

The point satisfy the inequality

ordered pair (2,4)

For x=2, y=4

substitute in the inequality

4>\frac{1}{2}(2)-2

4>-1 ---> is true

so

The point satisfy the inequality

therefore

The set contains only points that satisfy the inequality

case C) {(1, -1), (-3, -3), (4, -2)}

ordered pair (4,-2)

For x=4, y=-2

substitute in the inequality

-2>\frac{1}{2}(4)-2

-2>0 ---> is not true

therefore

The point not satisfy the inequality

case D) {(-1, -3), (-3, -3), (2, 4)}

ordered pair (-1,-3)

For x=-1, y=-3

substitute in the inequality

-3>\frac{1}{2}(-1)-2

-3>-2.5 ---> is not true

therefore

The point not satisfy the inequality

4 0
3 years ago
Solve for
faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
7 0
3 years ago
Read 2 more answers
CAN SOMEONE PLZZ HELP WIT THIS!!!!!
Shtirlitz [24]

Answer:

B

Step-by-step explanation:

b and a=40⁰ so if b+c is supplementary they equal 180⁰ together so 180-40= 150⁰

6 0
3 years ago
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The sum of 3 consecutive even numbers is 270 what is the first number in this sequence?
ad-work [718]

See picture for answer and solution steps.

6 0
3 years ago
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