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Amiraneli [1.4K]
3 years ago
12

Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.400 mmmm wide. The diffraction pattern is obse

rved on a screen 2.90 mm away. Define the width of a bright fringe as the distance between the minima on either side.
Required:
a. What is the width of the central bright fringe?
b. What is the width of the first bright fringe on either side of the central one?
Physics
1 answer:
erik [133]3 years ago
3 0

Answer:

a

 y_1 = 0.004589 \ m

b

 y_2 =0.009179 \  m

Explanation:

From the question we are told that

   The wavelength of the red light is  \lambda _r  = 633 \ nm  =  633 *10^{-9} \  m

    The width of the slit is  d = 0.40 mm = 0.40 *10^{-3} \  m

    The distance of the screen from the point of diffraction is D  =  2.9 \  m

Generally the width of the central bright fringe is mathematically represented as

       y_1 = \frac{\lambda * D}{d}

=>    y_1 = \frac{633 *10^{-9} * 2.90 }{0.40 *10^{-3}}

=>    y_1 = 0.004589 \ m

Generally the width of the first bright fringe on either side of the central one is mathematically represented as

     y_2 = 2 * y_1

=>   y_2 = 2 * 0.004589

=>   y_2 =0.009179 \  m

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