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Cloud [144]
3 years ago
7

Newer telephone circuits, built during the last decade, offer higher quality because they were built using analog transmission.

True False
Physics
1 answer:
hammer [34]3 years ago
6 0

Answer:

Well, newer telephone circuits built during the last decade are based on the digital transmission, not on the analog transmission. So it's the digital transmission circuit that has made the higher quality. Digital circuits converts the voice signals into the binary codes which is then translated again into the voice signal at the receiving end.

The answer is false.

Explanation:

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A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the d
timofeeve [1]
Perpendicular acceleration:
F = ma
a = 4 / 2 = 2 m/s²

Perpendicular distance:

s = ut + 1/2 at²
s = 0 x 4 + 1/2 x 2 x 4²
s = 16 m

Horizontal distance:
s = ut
= 3 x 4
= 12 m

Total distance = √(12² + 16²)
= 20 m.
3 0
3 years ago
The acceleration due to gravity on the moon is about 5.4ft/s2. if your weight is 150lbf on earth
Ivenika [448]

... then your weight is <em>25.2 lbf</em> on the moon.

6 0
3 years ago
4. Who was the proponent of the Neo-classicism? a) Claude Debussy b) Joseph Maurice Ravel c) Igor Stravinsky d) Arnold Schoenber
nirvana33 [79]

Who was the proponent of the Neo-classicism?

a) Claude Debussy

b) Joseph Maurice Ravel

c) Igor Stravinsky

d) Arnold Schoenberg

4 0
3 years ago
The tallest building in the world, according to some architectural standards, is the Taipei 101 in Taiwan, at a height of 1671 f
Andrej [43]

Answer:

35.14°C

Explanation:

The equation for linear thermal expansion is \Delta L = \alpha L_0\Delta T, which means that a bar of length L_0 with a thermal expansion coefficient \alpha under a temperature variation \Delta T will experiment a length variation \Delta L.

We have then \Delta L = 0.481 foot, L_0 = 1671 feet and \alpha = 0.000013 per centigrade degree (this is just the linear thermal expansion of steel that you must find in a table), which means from the equation for linear thermal expansion that we have a \Delta T =\frac{\Delta L }{\alpha L_0} = 22.14°. As said before, these degrees are centigrades (Celsius or Kelvin, it does not matter since it is only a variation), and the foot units cancel on the equation, showing no further conversion was needed.

Since our temperature on a cool spring day was 13.0°C, our new temperature must be T_f=T_0+\Delta T = 35.14°C

3 0
3 years ago
Calculate the rate of heat conduction through a layer of still air that is 1 mm thick, with an area of 1 m, for a temperature of
max2010maxim [7]

Answer:

The rate of heat conduction through the layer of still air is 517.4 W

Explanation:

Given:

Thickness of the still air layer (L) = 1 mm

Area of the still air = 1 m

Temperature of the still air ( T) = 20°C

Thermal conductivity of still air (K) at 20°C = 25.87mW/mK

Rate of heat conduction (Q) = ?

To determine the rate of heat conduction through the still air, we apply the formula below.

Q =\frac{KA(\delta T)}{L}

Q =\frac{25.87*1*20}{1}

Q = 517.4 W

Therefore, the rate of heat conduction through the layer of still air is 517.4 W

6 0
3 years ago
Read 2 more answers
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