What’s the answer to this question pls help

Explain (in words) why Li produces spectral lines and why it appears pink in the firework?

Brilliant_brown [7]

Answer:

Color tells us about the temperature of a candle flame. The inner core of the candle flame is light blue, with a temperature of around 1670 K (1400 °C). That is the hottest part of the flame. The color inside the flame becomes yellow, orange, and finally red. The further you reach from the center of the flame, the lower the temperature will be. The red portion is around 1070 K (800 °C).

The orange, yellow, and red colors in a flame do not relate only to color temperature. Gas excitations also play a major role in flame color. One of the major constituents in a burning flame is soot, which has a complex and diverse composition of carbon compounds. The variety of these compounds creates a practically continuous range of possible quantum states to which electrons can be excited. The color of light emitted depends on the energy emitted by each electron returning to its original state.

Within the flame, regions of particles with similar energy transitions will create a seemingly continuous band of color. For example, the red region of the flame contains a high proportion of particles with a difference in quantum state energies that corresponds to the red range of the visible light spectrum.

Explanation:

6 0

3 years ago

How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen

NeTakaya

MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

c = 0.5 mol/L

V = 1 L

n = c * V

n = 0.5 mol/L * 1 L = 0.5 mol

m = n * M

m = 0.5 mol * 60 g/mol = 30 g/mol

answer E

(-_-(-_-)-_-)

3 0

3 years ago

Which solution has the lowest freezing point?

Leokris [45]

Correct Answer: Option 3 i.e. 30 g of KI dissolved in 100 g of water.

Reason:
Depression in freezing point is a colligative property and it is directly proportional to molality of solution.

Molality of solution is mathematically expressed as,
Molality = $\frac{\text{Number of moles}}{\text{Weight of solvent (Kg)}}$ 

In case of option 1 and 2, molality of solution is 0.602 m. For option 3, molality of solution is 1.807 m, while in case of option 4, molality of solution is 1.205 m.

Thus, second solution (option 2) has highest concentration (in terms of molality). Hence, it will have lowest freezing point

3 0

4 years ago

Read 2 more answers

How can u detect the which d-orbital is used in making bond ??

zavuch27 [327]

This is much more simple than it sounds...

s has 1 orbital; p = 3 orbitals; d= 5 orbitals; f= 7 orbitals. (you just need to memorize this)
A maximum of 2 electrons can occupy each orbital.

The number of orbitals that each atom has is based on the number of electrons it has and by consequence it's position on the periodic table. 

The orbitals occur in sequence. Whereby electrons fill first from the lowest energy level (1s) outwards to the highest.
3p = the following sequence.
1s, 2s, 2p, 3s, 3p: these 'sets' can hold the following electrons respectively (2+2+6+2+6) 18 which corresponds with argon on the periodic table. REMEMBER p has 3 orbitals, d has 5 orbitals. So, here there are 9 orbitals.

The sequence through n=4 is:

1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

4 years ago

Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym

DedPeter [7]

Answer:

8.32 s⁻¹

Explanation:

Given that:

The concentration of myosin = 25 pmol/L

R_max = 208 pmol/L/s

The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.

In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.

The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.

The turnover number of the enzyme molecule of myosin can be calculated by the expression: $\dfrac{R_{max}}{concentration}$

⇒ $\dfrac{208 pmol/L/s}{25 pmol/L}$

= 8.32 s⁻¹

4 0

4 years ago