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2 years ago

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PLEASE HELP (50 POINTS)

1 answer:

faltersainse [42]2 years ago

7 0

1.F

2.T

3.T

4.T

good luck

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Anit [1.1K]

Well the area of a trapezoid is defined by the following formula:
A = $\frac{1}{2}(b_{1} + b_{2})h$ where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = $\frac{1}{2} (15+25)(7)=140$

This is in square units of measure of course, so 140 in²

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A small plane's maximum takeoff weight is 2000 pounds or less. six passengers weigh an average of 150 pounds each. use an inequ

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Read 2 more answers

A The length of a rectangle is 4 m more

Lady bird [3.3K]

Given :

The length of a rectangle is 4m more than the width.
The area of the rectangle is 45m²

⠀

To Find :

The length and width of the rectangle.

⠀

Solution :

We know that,

$\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:$

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

$\qquad \sf \: { \dashrightarrow x \times (x - 4) = 45 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 4x = 45 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 4x - 45 = 0 }$

$\qquad \sf \: { \dashrightarrow {x}^{2} - 9x+ 5 x - 45 = 0 }$

$\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }$

$\qquad \sf \: { \dashrightarrow (x - 9) (x + 5) = 0 }$

$\qquad \sf \: { \dashrightarrow x = 9, \: \: x = - 5}$

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

$\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:$

$\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:$

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