Answer:
6.54% is the required concentration of lithium in an alloy (Al–Li).
Explanation:
Suppose 100 grams of an alloy of aluminium and lithium.
Density of an alloy = d 
Volume of an alloy = V

Volume of aluminum = 
Mass of aluminum = x
Density of aluminum = 

Volume of lithium = 
Mass of lithium = y
Density of lithium= 

..[1]


..[2]
Solving [1] and [2] :
we get :
x = 93.46 g
y = 6.54 g
Concentration of Li (in wt%) that is required:

Yes because the equation is balanced!
Answer:
This is because an increase in temperature increases the movement of molecules/particles of reactants which encourages collision and subsequently, reaction.
C7H14 + 10.5 O2 -> 7 CO2 + 7 H2O
Or, if whole numbers must be used:
2 C7H14 + 21 O2 -> 14 CO2 + 7 H2O