Answer:
ok so we have to make it so we can get rid of one of the varibles by adding or subtracting
so lets multiply the first one by 4
120x+16y=4160
minus the second one so
108x=2160
divide by 108
x=20
then we just plug in
12(20)+16y=2000
240+16y=2000
-240
16y=1760
divide by 16
y=110
(20,110)
Hope This Helps!!!
If the answer is D. the equation to represent the ages of students is:
n + n+1 + n+2 = 45
it is showing that n is the age of one student and the other student has age one year more than the first one and third students has age of 2 years more than first student and one year greater than the second student. if we solve this equation for the value of n, we get;
3n + 3 = 45
3n = 45 -3
3n = 42
n = 14
so the age of one student is 14, second student 15 and third student 16 years.
and if we add there ages, 14 + 15 + 16 = 45
(5x^2-15x) (-2x+6)
5x (x-3) -2 (x-3)
(5x-2) (x-3)
6 months
Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
