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hodyreva [135]
3 years ago
15

Evaluate the expression when n=3 60n(2 - n) = ?

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
The answer is -180..
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Solve for xx. Round to the nearest tenth of a degree, if necessary.
Ghella [55]

Answer: 48.1^{\circ}

Step-by-step explanation:

\sin x=\frac{7}{9.4} \\ \\ x=\sin^{-1} \left(\frac{7}{9.4} \right) \approx \boxed{48.1^{\circ}}

6 0
2 years ago
Find the percent of increase from 40 gallons to 89 gallons. Round to the nearest tenth of a percent if necessary.
fredd [130]

Solution

- 89 gallons contains 40 gallons twice such that:

89=40+40+9

- This means that we can find at least 200% of 40 gallons in 89 gallons. This gives us what to expect.

- To get the percentage we are looking for, we should use the formula:

\frac{\text{new}}{\text{old}}\times100\text{ \%}

New, in this case, is 89 gallons, Old is 40 gallons.

- Thus, we can calculate the percentage as follows:

\begin{gathered} \frac{89}{40}\times100 \\ =2.225\times100 \\ =222.5\text{ \%} \end{gathered}

Thus, the answer is 222.5%

8 0
1 year ago
Write an integer for a profit of 12
Leona [35]
The answer is +12 because you add on 12
3 0
3 years ago
Read 2 more answers
What numbers does the square root of 82 fall between?
lesantik [10]
Between 9 and 10

Because 9 times 9 = 81 and 10 times 10 = 100
3 0
3 years ago
A carnival game allows a group of players to each draw and keep a marble from a bag. The bag contains 5 gold marbles, 25 silver
laila [671]
1. What’s the probablity of a second person winning the small prize?
There are now 99 total marbles, and 24 silver marbles. So, 24/99 is 0.24 probability.
2. Which player is most likely to win a big prize?
Since each player draws a silver marble (aka a small prize) there are less small prize marbles in the bag after each turn. So, the first person would have a 5% chance (or 0.05)of winning the big prize gold marble, but the last person would have a slightly bigger chance (5.15% or 0.0515) of winning a big prize.
3. How could the game be made fair for each player?
Well it’s quite simple, just have each player return their marble and the number of marbles would be kept constant, giving everyone an equal chance. Or you could have them all play at the same time, either way.
4. Same answer as 3
3 0
4 years ago
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