What is the area of area of 7 meters, 15 meters and 9 meters?

Mathematics

2 answers:

tatiyna2 years ago

7 0

Can you be more specific?

chubhunter [2.5K]2 years ago

3 0

Answer:

Step-by-step explanation:

10-7 do it yourself and don't vheat

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How do I find the range of this rational function, how do I do the steps in order to find it, please help!!!

Sindrei [870]

Answer:

Range= (0,∞) and (-∞,0)

Step-by-step explanation:

Theres no real process to finding this out you just look at what type of function you have, your graph and your asymptote. We can see that the parts above the asymptote go up and towards ∞ and the part below goes down to -∞ but they can not cross 0

8 0

2 years ago

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Blank divided by 6=0.2

mario62 [17]

Just do 6 x 0.2 to reverse the division
So the answer is 1.2

I think

4 0

2 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers: