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3 years ago

12

What is the average speed of 249 miles and 4 hours and 58 minutes

1 answer:

Andrej [43]3 years ago

7 0

(249 mi)/(4 58/60 h) ≈ 50.13 mi/h

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Gordon types 3,300 words in 50 minutes. Find the unit rate.

Doss [256]

Answer:

Step-by-step explanation:

All you need o divide 3,300 by 50

3300

÷ 50

--------------

66

so ever minute he would most likely type 66 words

5 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

8 0

3 years ago

Please help with this and explain how to do it, I'll give 15 points

MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = $\frac{10}{2}$ = 5 cm

Volume of the outer ball $V_{1}$ = $\frac{4}{3}\pi (r)^3$

= $\frac{4}{3}\pi (5)^3$

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball $V_{2}$ = $\frac{4}{3}\pi (4)^3$

Volume of the metal used in the metallic ball = $V_{1}-V_{2}$

= $\frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}$

= $\frac{4}{3}\pi [(5)^3-(4)^3]$

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0

3 years ago

How many ziros in the number 1.8e10?

Damm [24]

<span>You spelt zero wrong and theres one zero next to the 1. Comments; Report. 0 0 0. Thanks. 0. Log in to add a comment · 12ilett; Beginner</span>

8 0

4 years ago

Simplify the expression.

Ad libitum [116K]

Answer:

-10p/3+32-3/2^p

Step-by-step explanation:

8 0

2 years ago