A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N
b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
Answer:
a) B=0.008 T
b) +z direction
Explanation:
<u>solution:</u>
a) The magnetic force:
F=i*l*B
Solve for B:
B=0.008 T
b) According to the left hand rule, the magnetic field is in the +z direction
Answer:
a) -31.36 m/s
b) 50.176 m
Explanation:
<h2>a) Velocity of the bag</h2>
This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:
(1)
Where:
is the final velocity of the supply bag
is the initial velocity of the supply bag (we know it is zero because we are told <u>it was "dropped", this means it goes to ground in free fall</u>)
is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)
is the time
Knowing this, let's solve (1):
(2)
Hence:
Note the negative sign is because the direction of the bag is downwards as well.
<h2>b) Final height of the bag</h2>
In this case we will use the following equation:
(3)
Where:
is the distance the bag has fallen
remembering <u>the bag was dropped</u>
is the acceleration due gravity (downwards)
is the time
Then:
(3)
(4)
Finally:
Answer:
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