Question

What is the equation of the Points (4,3) and (-2,0)

Answer 1

Answer:

Step-by-step explanation:

The model equation: y = mx + b

First, we should find the slope. The equation is

$\frac{y2 - y1}{x2-x1}$

The numbers in the equation stand for the y or x variable from either the first or second point. So, we plug in the numbers and get,

$\frac{3-0}{4-(-2)}$

$\frac{3}{4+2}$ = $\frac{3}{6}$ = $\frac{1}{2}$

What we have right now is y = 1/2x + b. To solve for b (the y-intercept), we have to take one of the points and plug in the x and y variables. If we take the first point, the equation becomes,

3 = 1/2(4) + b

3 = 2 + b

b = 3 - 2

b = 1

The final equation is,

y = $\frac{1}{2}$x + 1