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Answer:
Coordinate geometry is one of the most important and exciting ideas of mathematics. In particular it is central to the mathematics students meet at school. It provides a connection between algebra and geometry through graphs of lines and curves. This enables geometric problems to be solved algebraically and provides geometric insights into algebra.
The invention of calculus was an extremely important development in mathematics that enabled mathematicians and physicists to model the real world in ways that was previously impossible. It brought together nearly all of algebra and geometry using the coordinate plane. The invention of calculus depended on the development of coordinate geometry.
Explanation:
Mass=density·volume. The density is 2.70g/mL and the volume is 353mL. So you would multiply 2.70g/mL by 353mL which will give you 953.1g. Hope that helps :)
The fluctuations in abiotic cycles can influence the population in many ways. The population of a particular area depends on the various abiotic cycles such as nitrogen cycle, carbon cycle, phosphorous cycle. The changes in these cycles affects the life of population. Fluctuation results in hibernation of species. Some of the organisms migrate to another place in search of normal environment. The early breeding results in creating problems. It disturbs the ecological balance by using the limited supply of resources. The fluctuation in phosphorous cycle can affect the aquatic population. As the dependency of population on abiotic cycles is as important as the biotic factors the fluctuations can cause many problem.
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Answer and Explanation:
The galvanic cell is:
Cu(s)| Cu²⁺(aq)|| Cu⁺(aq)| Cu(s)
The first two species before the double bar (||) constitute the <em>anodic half reaction (oxidation)</em>:
Cu(s) ⇒ Cu²⁺(aq) + 2 e-
The two species after the || constitute the <em>cathodic half reaction</em><em> </em><em>(reduction</em>):
Cu⁺(aq) + e- ⇒ Cu(s)
If we multiply the reduction half reaction by 2 (to obtain the same number of electrons than oxidation reaction) and then we add the two half reactions, we obtan the balanced equation:
Reduction (cathode) : 2Cu⁺(aq) +2 e- ⇒ 2Cu(s)
Oxidation (anode) : Cu(s) ⇒ Cu²⁺(aq) + 2 e-
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Total equation: 2Cu⁺(aq) + <em>Cu(s)</em> ⇒ <em>2Cu(s)</em> + Cu²⁺(aq)
Cu(s) is in both reactants side and products side, so we cancel that in both opposite sides to obtain:
2Cu⁺(aq) ⇒ Cu(s)<em> </em>+ Cu²⁺(aq)
If we divide the balanced equation into 2, the smallest possible integer coefficient for Cu⁺(aq) is 1:
Cu⁺(aq) ⇒ 1/2 Cu(s)<em> </em>+ 1/2 Cu²⁺(aq)