Question

A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the first two minutes. what would be the angular acceleration of the merry-go-round in rpm/min?

Answer 1

initially marry go round is at rest

after t= 2 minutes its final angular speed is 4 rpm

$w_f = 2 \pi *\frac{4}{60}$

$w_f = 0.42 rad/s$

now by using kinematics we will have

$w_f = w_0 + \alpha * t$

$0.42 = 0 + \alpha * (2*60)$

$\alpha = 3.5 * 10^{-3} rad/s^2$

$\alpha = 3.5 * 10^{-3} * \frac{60*60}{2\pi}$

$\alpha = 2 rev/min^2$