Explanation:
Let magnitude of the two forces be x and y.
Resultant at right angle R1= √15N) and at
60 degrees be R2= √18N.
Now, R1 = √(x² + y²) = √15,
R2= √(x² + y² +2xycos50) = √18.
So x² + y² = 15,
and x² + y² + 1.29xy = 18,
therefore 1.29xy = 3,
y = 3/1.29x.
y = 2.33/x
Now, x2 + (2.33/x)2 = 15,
x² + 5.45/x² = 15
multiply through by x²
x⁴ + 5.45 = 15x²
x⁴ - 15x2 + 5.45 = 0
Now find the roots of the equation, and later y. The two values of x will correspond to the
magnitudes of the two vectors.
Good luck
Change in thermal energy not always cause it's temperature change. It is the situation when water reaches either at 0 C or 100 C then thermal energy doesn't cause change in temperature instead it changes the state of matter.
In short, Your Answer would be "True"
Hope this helps!
Explanation:
1. The entire span of possible sound waves is called the acoustic spectrum. It is subdivided into infrasonic sounds, audible sounds, and ultrasonic sounds.
2. The difference between a musical note and another note at twice the frequency is called an octave.
3. Sound intensity varies with the inverse square of distance.
Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:
Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:
In words, the value of q₃ must be 5.3nC.
Answer:
3.528×10² V.
Explanation:
potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,
V = kq/r..................... Equation 1
And
E = kq/r² .................. Equation 2
Comparing equation 1 and equation 2,
V = E×r............................. Equation 3
Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.
Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.
Substitute into equation 3,
V = 6.3×10⁵×0.00056
V = 3.528×10² V.
Hence the potential difference of the plate = 3.528×10² V.
