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3 years ago

A ball is thrown in the air with a vertical velocity of 12 m/s.

Physics

2 answers:

melamori03 [73]3 years ago

4 0

The answer to the question is gonna be A

Ipatiy [6.2K]3 years ago

4 0

Answer:

a) 1.22 s

b) 6 m/s

c) 7.35 m

Explanation:

Given:

v₀ = 12 m/s

a = -9.8 m/s²

a) Find t when v = 0 m/s.

v = at + v₀

(0 m/s) = (-9.8 m/s²) t + (12 m/s)

t = 1.22 s

b) v_avg = ½ (v₀ + v)

v_avg = ½ (12 m/s + 0 m/s)

v_avg = 6 m/s

c) Find Δx.

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2 (-9.8 m/s²) Δx

Δx = 7.35 m

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3 years ago

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Now put the values of y" , y' and y in equation 1

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So by comparing the coefficient both sides

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$m^2+8m+16=0$

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$Y=(C_1+tC_2)e^{-2t}-3/16 cos 4t$

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$C_1=\dfrac{3}{16}$

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3 years ago

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3 years ago

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elena-14-01-66 [18.8K]

Answer:

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