A ball is thrown in the air with a vertical velocity of 12 m/s.
2 answers:
The answer to the question is gonna be A
Answer:
a) 1.22 s
b) 6 m/s
c) 7.35 m
Explanation:
Given:
v₀ = 12 m/s
a = -9.8 m/s²
a) Find t when v = 0 m/s.
v = at + v₀
(0 m/s) = (-9.8 m/s²) t + (12 m/s)
t = 1.22 s
b) v_avg = ½ (v₀ + v)
v_avg = ½ (12 m/s + 0 m/s)
v_avg = 6 m/s
c) Find Δx.
v² = v₀² + 2aΔx
(0 m/s)² = (12 m/s)² + 2 (-9.8 m/s²) Δx
Δx = 7.35 m
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