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enot [183]
3 years ago
8

A ball is thrown in the air with a vertical velocity of 12 m/s.

Physics
2 answers:
melamori03 [73]3 years ago
4 0
The answer to the question is gonna be A
Ipatiy [6.2K]3 years ago
4 0

Answer:

a) 1.22 s

b) 6 m/s

c) 7.35 m

Explanation:

Given:

v₀ = 12 m/s

a = -9.8 m/s²

a) Find t when v = 0 m/s.

v = at + v₀

(0 m/s) = (-9.8 m/s²) t + (12 m/s)

t = 1.22 s

b) v_avg = ½ (v₀ + v)

v_avg = ½ (12 m/s + 0 m/s)

v_avg = 6 m/s

c) Find Δx.

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2 (-9.8 m/s²) Δx

Δx = 7.35 m

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Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

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where,

m_c = mass of copper = 227 g

m_w = mass of water = 844 g

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\Delta T_c = change in temperature of copper = 283°C - T

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\Delta T_a = change in temperature of aluminum = T - 14.6°C

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Therefore,

(227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}

<u>T = 20.84°C</u>

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