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yulyashka [42]
3 years ago
11

sketch a velocity time graph for the motion of the body . from the graph explain each step, calculate the total distance covered

by the body

Physics
1 answer:
Tatiana [17]3 years ago
5 0

Answer: please find the attached file for the solution.

Explanation:

In a velocity time graph for the motion of the body, the total distance covered by the body is area under the graph.

Please find the attached file for the solution.

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Draw the ray diagram of Radius of concave mirror=7cm
seropon [69]

Answer:

Nature and size of image:

the image is formed at the focus (F), the image is virtual,erect and highly diminished.

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3 years ago
Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we
jeka57 [31]

(a) 4.14 rad/s^2

The relationship beween centripetal acceleration and angular speed is

a=\omega^2 r

where

\omega is the angular speed

r is the radius of the circular path

Here we gave

a = 9g = 88.2 m/s^2 is the centripetal acceleration

r = 5.15 m is the radius

Solving for \omega, we find:

\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the radius of the circular path

In this problem we have

\omega=4.14 rad/s

r = 5.15 m

Solving the equation for v, we find

v=(4.14 rad/s)(5.15 m)=21.3 m/s

7 0
3 years ago
Read 2 more answers
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kifflom [539]
In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀

where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â

Since d = 2 · r, we can write:
d = n² · d₀
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Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
8 0
3 years ago
A proton of mass is released from rest just above the lower plate and reaches the top plate with speed . An electron of mass is
xenn [34]

Answer:

  v = √ 2e (V₂-V₁) / m

Explanation:

For this exercise we can use the conservation of the energy of the electron

At the highest point. Resting on the top plate

         Em₀ = U = -e V₁

At the lowest point. Just before touching the bottom plate

        Emf = K + U = ½ m v² - e V₂

Energy is conserved

         Em₀ = Emf

          -eV₁ = ½ m v² - e V₂

           v = √ 2e (V₂-V₁) / m

Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron

3 0
4 years ago
The quark composition of the proton and neutron are, respectively, uud and udd, where u is an up quark (charge +23e) and d is a
ludmilkaskok [199]

Answer:

Option C=> π+.

Explanation:

Just as it is given in the question above, we can see that the addition or combination of proton and neutron gives what is known as QUARKS.

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The study of Quarks is very important in physics because they relate very well with electromagnetic force, strong force, weak force and Gravitational force.

"...When the remaining quarks combine to form a single particle, it is a π+".

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8 0
3 years ago
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