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Pie
3 years ago
9

Compare the resistance of a 1.5-Amp interior light bulb of a car (operating off a 12-V battery) to the

Physics
1 answer:
OLga [1]3 years ago
8 0

Answer:

The resistance of the internal light bulb of the car is higher than that of the household circuitry.

Explanation:

Given the following data;

I. Current = 1.5 A

Voltage = 12 V

To find the resistance;

Voltage = current * resistance

12 = 1.5 * resistance

Resistance = 12/1.5

Resistance = 8 Ohms

II. Power = 100 Watt

Voltage = 110 V

To find the resistance;

Power = voltage/resistance²

100 = 110/resistance²

Cross-multiplying, we have;

100resistance² = 110

R² = 110/100

R² = 1.1

Taking the square root of both sides, we have;

R = √1.1

R = 1.05 Ohms

Therefore, the resistance of the internal light bulb of the car is higher than that of the household circuitry.

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From E=hf we can see that energy is directly proportional to frequency since h is a constant, this implies that as we move up the visible light spectrum, red light has the least frequency this accounting for the lowest energy while violet has the largest energy accounting for a very high energy.

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