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8090 [49]
3 years ago
13

Estado de oxidación de doro​

Chemistry
1 answer:
ad-work [718]3 years ago
3 0

Answer:

Entonces, ¿cuál es tu pregunta? No veo una foto

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What is one similarity between metals and metalloids?
Arturiano [62]

The correct answer that explains similarities between metal and Metalloids as regards the question is They both conduct electricity

  • Metalloids can be regarded as elements that are  similar to metals, this is because they posses valence orbitals which is described as highly delocalized over macroscopic volumes.

  • As a result of this they can serve as electrical conductors.

  • metalloids posses small energy gap which is located between the valence band as well as the conduction band, as a result of this they are considered as  intrinsic semiconductors when compare to pure conductors like metal.

  • Example of metal is Calcium, sodium and that of Metalloids are silicon and  germanium

Therefore, metal and Metalloids are similar because of their conductivity of electricity

Learn more at: brainly.com/question/21036799?referrer=searchResults

4 0
2 years ago
In a chemcial reaction, substances
Fofino [41]

Answer:

My guess is c

Explanation:

5 0
3 years ago
I need help asap thank u
UNO [17]
It is b, i learned this last year hope this helps
4 0
3 years ago
Really need help!
WARRIOR [948]
The magnitude of a star as it would appear to a hypothetical observer at a distance of 10 parsecs or 32.6 light-years. This rates how visible celestial bodies are when they are all viewed from the same distance. Luminosity: The brightness of a star in comparison with that of the sun.
7 0
3 years ago
Read 2 more answers
You are given an unknown gaseous binary compound (that is, a compound consisting of two different elements). when 10.0 g of the
Luda [366]

Answer is: a possible identity for the unknown compound is C₃H₈.

m(binary compound) = 10.0 g.

m(H₂O) = 16.3 g; mass of water.

M(O₂) = 32 g/mol; molar mass of oxygen.

M(binary compound) = 1.38 · 32 g/mol.

M(binary compound) = 44.16 g/mol.

n(binary compound) = 10 g ÷ 44.16 g/mol.

n(binary compound) = 0.225 mol; amount of substance.

n(H₂O) = 16.3 g ÷ 18 g/mol.

n(H₂O) = 0.9 mol; amount of water.

m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.

m(H₂O) : n(binary compound) = 4 : 1.

Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.

Second element in compound is carbon:

M(X) = 44.16 g/mol - 8 · 1.01 g/mol.

M(X) = 36.08 g/mol ÷ 3.

M(C) = 12.01 g/mol.

8 0
2 years ago
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