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2 years ago

Please help me with geometry

Mathematics

1 answer:

mariarad [96]2 years ago

3 0

Answer:

x = 8

Step-by-step explanation:

Set 2x + 3 = 3x - 5

Solve for x

x = 8

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Solve for x. x = [?] 4x - 2 3x + 14

Ilya [14]

Answer:

X = 7

Step-by-step explanation:

I really don’t know

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3 years ago

Bob recorded the number of hours each person watched TV in a week. He then organized the information in a frequency table.

seraphim [82]

Answer:

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Step-by-step explanation:

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3 years ago

In a theatre seats are arranged in rows. A teacher took her team of 50 students to the theatre for a field trip.there are 6 rows

lord [1]

48*465=8462*585655*446=745

7 0

3 years ago

So far, Ricardo has scores of 13, 17, 19 and 21 points for the first four rounds of a dice game. What does he need the total sco

posledela

Answer:

40 points

Step-by-step explanation:

The score for the first four rounds of the game is 13, 17, 19, and 21 points.

Let $S_5$ and $S_6$ be the scores of the fifth and sixth games respectively in order to achieve an average score of 20 points per round for all six rounds.

$\text{Average score} = \frac{\text{Sum of the scores of all the rounds}}{\text{Total number of the rounds}}$

$\Rightarrow 20=\frac{13+17+19+21+S_5+S_6}{6}$

$\Rightarrow 20\times6=80+S_5+S_6$

$\Rightarrow S_5+S_6=120-80=40.$

Hence, the combined score of the fifth and sixth rounds are 40 points.

3 0

3 years ago

If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?

Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

20 * 20 * 20 * 20 * 20

First number 2nd number 3rd number 4th number 5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are $20^{5}$ ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

15 * 15 * 15 * 15 * 15

First number 2nd number 3rd number 4th number 5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are $15^{5}$

So the probability P can be calculate as:

$P=\frac{15^{5} }{20^{5} } \\P=0.2373$

Then the probability that their minimum is larger than 5 is 0.2373

7 0

3 years ago