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alina1380 [7]
3 years ago
12

Which of the following are hydrocarbons? Check all that apply. A. B. C. D.

Chemistry
2 answers:
lutik1710 [3]3 years ago
3 0

Answer:

its B and D

Explanation:

other person is wrong.

____ [38]3 years ago
3 0

Answer:

b and d

Explanation:

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Which statement best describes the movement of atoms in solid
ser-zykov [4K]
Atoms according to the kinetic molecular theory, are described in a solid to simply be vibrating in fixed positions, and not moving rapidly in the container. Because of this, they take a fixed volume and have fixed shape.
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Consider chemical reactions between main group metals and non-metals. Based on known bonding patters, which of the following com
Fittoniya [83]

Answer:

You didn't list the compounds it gave you so i cant cross check them to see it they are ionic bonds( which is  the chemical bonding is formed between metal and nonmetal)

if you reply with the compounds it list I will be happy to check for you

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2 years ago
Bacteria that can make food using chemicals are called
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False because I think it’s supposed to be photoheteroterotrophs
4 0
3 years ago
What element is being reduced in the redox reaction? H2O2+ ClO2- > ClO- + O2
slava [35]

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Cl

Explanation:

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6 0
3 years ago
A sample of substance X that has a mass of 326.0 g releases 4325.8 call when it freezes at its freezing point. If substance X ha
o-na [289]

Answer : The molar heat of fusion for substance X is, 775.6 cal/mol

Explanation :

First we have to calculate the moles of substance X.

\text{Moles of substance X}=\frac{\text{Mass of substance X}}{\text{Molar mass of substance X}}

Given:

Molar mass of substance X = 58.45 g/mole

Mass of substance X = 326.0 g

Now put all the given values in the above expression, we get:

\text{Moles of substance X}=\frac{326.0g}{58.45g/mol}=5.577mol

Now we have to calculate the molar heat of fusion for substance X.

\Delta H=\frac{Q}{n}

where,

Q = heat releases = 4325.8 cal

\Delta H = molar heat of fusion for substance X = ?

n = moles = 5.577 mol

Now put all the given values in the above expression, we get:

\Delta H=\frac{4325.8cal}{5.577mol}=775.6cal/mol

Thus, the molar heat of fusion for substance X is, 775.6 cal/mol

6 0
3 years ago
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