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Ghella [55]
3 years ago
12

9.The force of gravity between two asteroids is 10,000 newtons (N).

Physics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

F1 = G m1 m2 / R^2        force of attraction

F2 = G m1 m2 / (R/2)^2

F2 / F1 = 4       the force of gravity will be quadrupled

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Uses of hydrometer in points​
Arisa [49]

Answer:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water

7 0
3 years ago
Two long, straight parallel wires 8.2 cm apart carry currents of equal magnitude I. The parallel wires repel each other with a f
o-na [289]

Answer:

36.22 mA

Explanation:

i1 = I , i2 = I, d = 8.2 cm = 0.082 m

Force per unit length = 3.2 nN/m = 3.2 x 10^-9 N/m

μo = 4 π × 10^-7 Tm/A

The formula for the force per unit length between the two wires is given by

F = μo / 4π x (2 i1 x i2) / d

3.2 x 10^-9 = 10^-7 x 2 x I^2 / 0.082

I = 0.0362 A = 36.22 mA

4 0
4 years ago
Complete the steps for converting 3.6 gallons per minute to milliliters per second. (1 gallon = 3.79 liters and 1 liter = 1,000
AlekseyPX

Given that,

Capacity = 3.6 gallons per minutes

Convert it into milliliters per seconds

Since, 1 gallon = 3.79 liters

1 liters = 1000 milliliters

Capacity= (3.6*3.79*1000)/(60)

Capacity = 227.4 milliliters per second.

6 0
3 years ago
You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget
aleksklad [387]

Answer:

35.7 m

Explanation:

Let

\mid A\mid=18.5 m

\mid B\mid=41 m

We have to find the distance between Joe's and Karl'e tent.

A_x=Acos\theta

A_y=Asin\theta

Substitute the values then we get

A_x=18.5cos23^{\circ}=17 m

A_y=18.5sin 23^{\circ}=7.2 m

B_x=41cos37.5^{\circ}=32.5 m

B_y=41sin37.5^{\circ}=-24.96 m

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

B=A+C

C=B-A

C_x=B_x-A_x=32.5-17=15.5 m

C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m

\mid C\mid=\sqrt{C^2_x+C^2_y}

\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m

Hence, the distance between Joe's and Karl's tent=35.7 m

6 0
3 years ago
Can someone tell me if I’m correct or not
Anika [276]
You are correct because nothing is being done to the cake
6 0
3 years ago
Read 2 more answers
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