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Ghella [55]
3 years ago
12

9.The force of gravity between two asteroids is 10,000 newtons (N).

Physics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

F1 = G m1 m2 / R^2        force of attraction

F2 = G m1 m2 / (R/2)^2

F2 / F1 = 4       the force of gravity will be quadrupled

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If potential energy decreases will kinetic energy increase?
cestrela7 [59]

Answer:

yes

Explanation:

It's because as total energy remains constant, kinetic energy decreases potential energy increases. as an object moves the potential energy gradually gets decreased while kinetic energy increases so as to maintain energy constant.

5 0
3 years ago
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A meteor moving 468 km per minute traveling in a south-to-north direction passed near Earth in 2013. Does this statement describ
Thepotemich [5.8K]

Answer:

this statement describes meteor's velocity,

because velocity is a vector quantity which has both magnitude as well as a specific direction and here the meteor's direction is specified in the statement hence we conclude that this statement describes meteor's velocity as well as speed too.

3 0
3 years ago
The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be
Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>
  • It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
  • Mathematically, T²∝a³
<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
  • The time period of geosynchronous orbit is 24 hours or 1440 minutes.
  • As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
  • If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
  • a1= (T1/T2)⅔×a2

           = (1440/90)⅔×6780

           = 43,090 km

  • Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

brainly.com/question/16705471

#SPJ4

   

6 0
2 years ago
Type of force that keep objects moving in a circle or arv​
Svetlanka [38]

Answer: a net force

7 0
3 years ago
What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge
emmasim [6.3K]

Answer:

The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

Explanation:

Given that,

Force F= 4.00\times10^{-5}\ N

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

F = qE

E = \dfrac{F}{q}

E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}

E=-1.25\times10^{14}\ N/C

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

8 0
4 years ago
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