Answer:
v₂ = 5.7 m/s
Explanation:
We will apply the law of conservation of momentum here:
where,
Total Initial Momentum = 340 kg.m/s
m₁ = mass of bike
v₁ = final speed of bike = 0 m/s
m₂ = mass of Sheila = 60 kg
v₂ = final speed of Sheila = ?
Therefore,
<u>v₂ = 5.7 m/s </u>
Answer: a) 152 cm
b) 0.725 ms
c) 10°
Explanation:
Given
Frequency of the wave, f = 524 Hz
Speed of the wave, v = 345 m/s
Wavelength of the wave, λ = ?
The relation for wavelength is given by
λ = f/v, on substituting
λ = 524 / 345
λ = 1.52 m or 152 cm
T = 1/v
T = 0.0029 s
T = 2.9 ms.
Note that the phase change is 90°, thus the time required to change the phase by 90° is
t = 2.9 * (90 / 360)
t = 2.9 * 0.25
t = 0.725 ms
The phase difference at a particular instance 4.4 cm apart is
= (4.4 / 152) * 360
= 0.02895 * 360
= 10.422°
a) 152 cm
b) 0.725 ms
c) 10°
<span>Lightbulbs are filled with the element argon and the filaments are made of metallic element tungsten. The argon in the bulb protects the filament from the surrounding air, which would otherwise oxidize the filament. </span>
Answer:
increase, increase
Explanation:
If the bore of an engine is increased without any other changes except for the change to proper-size replacement pistons. the displacement will<u> increase </u>and the compression rate will <u>increase</u>.
Further Explanation:
If the bore is increased, there are several benefits to this. There is more area for the valves this improves flow through the engine. The compression ratio will increase, thereby increasing thermal efficiency. The displacement also increases as the power output increase. Also, higher RPM will further increase power.
However, a decrease in bore will result in corresponding reduction in displacement and power output.
The angular magnification of the microscope is 78.125.
<h3>What is angular magnification?</h3>
the ratio of the angle at the eye that an optical instrument's image occupies to the angle at the eye that an object occupies while not being viewed through an optical instrument is called as angular magnification.
Thus we can calculate it as:
- focal length of objective lens, fo = 1.6 cm
- focal length of the eyepiece, fe = 2.5 cm
- Distance between the lenses, L = 15 cm
- Least distance of distinct vision for normal eye, d = 25 cm
The formula for the magnification of the compound microscope is given by
M = - 78.125
Thus, the magnification of the compound microscope is 78.125.
Learn more about angular magnification here:
brainly.com/question/17327671
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