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Ostrovityanka [42]

3 years ago

6

What is the hottest layer in the Sun's atmosphere?

2 answers:

pychu [463]3 years ago

8 0

The hottest layer in the Sun's atmosphere is the core.

Allisa [31]3 years ago

3 0

It is chromosphere the hottest layer of sun's atmosphere

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if the volume of a scuba tank filled with air remains constant and its temperature goes down, what happens to its pressure?

Vladimir [108]

Answer:

Decreases

Explanation:

Ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is gas constant,

and T is absolute temperature.

If V is constant and T decreases, then P must decrease.

3 0

3 years ago

Can someone pleaseeee answer this !!!!!!

LenaWriter [7]

Answer:

The person with locked legs will experience greater impact force.

Explanation:

Let the two persons be of nearly equal mass (say m)

The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,

$v=\sqrt{2gH}$

( $g$ = acceleration due to gravity)

which can be derived from Newton's equation of motion,

$v^2=u^2+2aS$

Now, the time taken (say $t$ ) for the momentum ( $mv$ ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.

We know that,

$Force=\frac{\Delta(mv)}{t}$

Naturally, the person who bends his legs will experience lesser force since $t$ is larger.

3 0

3 years ago

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba

MakcuM [25]

At the very top of the peak and on the way down

7 0

4 years ago

Read 2 more answers

A compact car, mass 660 kg, is moving at 1.00 ✕ 102 km/h toward the east. The driver of the compact car suddenly applies the bra

Maslowich

Answer: $59.43\times 10^3 kg-m/s$

Explanation:

Given

mass of car $m=660 kg$

Initial velocity of car $=102 km/h\approx 28.33 m/s$ towards east

Time taken to stop $t=2.1 s$

Force exerted $F_{avg}=4.8\times 10^3 N$

change in momentum is given by impulse imparted to the car

$Impulse(J)=-F\cdot t$

$J=-4.8\times 10^3\times 2.1$

$J=-59.49\times 10^3 kg-m/s$

negative Sign indicates that impulse is imparted opposite to the direction of motion

magnitude of momentum $J=59.49\times 10^3$

6 0

3 years ago

Read 2 more answers

Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150

Sever21 [200]

Answer: $2.89\approx 2.9^{\circ}C/s$

Explanation:

Given

$Power\left ( P\right )=150 MW$

mass of core $\left ( m\right )=1.60\times 10^5 kg$

Average specific heat $\left ( C\right )=0.3349 KJ/kg^{\circ}C$

And rate of increase of temperature = $\frac{\mathrm{d}T}{\mathrm{d} t}$

Now

P= $mc\frac{\mathrm{d}T}{\mathrm{d} t}$

$150\times 10^6=1.60\times 10^5\times 0.3349\times \frac{\mathrm{d}T}{\mathrm{d} t}$

Thus $\frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}$

$\frac{\mathrm{d}T}{\mathrm{d} t}=2.89\approx 2.9^{\circ}C/s$

6 0

4 years ago