Answer:
Explanation:
What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.
horizontal velocity component
vx = 55.0/2.50 = 22 m/s
vertical initial velocity component
(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²
vy₀ = 13.0625 m/s
θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°
Answer:
<u>12.5m/s</u>
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = <u>12.5</u>
Answer: its the second (B) option, n1sintheta1=n2aintheta2
theta is the thing that looks like a 0 with the across.
Explanation: I got it right
Answer:
Pressure at P point is given as

Explanation:
As we know by poiseuille's equation of viscous flow of liquid through cylindrical pipe

here we know that
L = 4 cm

r = 1 mm
Q = flow rate





now we have



Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m