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Ostrovityanka [42]
3 years ago
6

What is the hottest layer in the Sun's atmosphere?

Physics
2 answers:
pychu [463]3 years ago
8 0

The hottest layer in the Sun's atmosphere is the core.

Allisa [31]3 years ago
3 0
It is chromosphere the hottest layer of sun's atmosphere
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In the popular game "Angry Birds" (refer Figure), for the red bird to hit the green bird with their range 55.0 m, what should be
Inga [223]

Answer:

Explanation:

What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.

horizontal velocity component

vx = 55.0/2.50 = 22 m/s

vertical initial velocity component

(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²

vy₀ = 13.0625 m/s

θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°

4 0
3 years ago
A horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
skelet666 [1.2K]

Answer:

<u>12.5m/s</u>

Explanation:

Simplify the proportion.

200/16 = 100/8 = 50/4 = 25/2 = <u>12.5</u>

5 0
3 years ago
Which formula represents Snell’s law?
inysia [295]

Answer: its the second (B) option, n1sintheta1=n2aintheta2

theta is the thing that looks like a 0 with the across.

Explanation: I got it right

6 0
3 years ago
Read 2 more answers
The figure shows a water-filled syringe with a 4.0-cm-long needle. What is the gauge pressure of the water at the point P, where
mars1129 [50]

Answer:

Pressure at P point is given as

P_p = 1.042 \times 10^5 Pa

Explanation:

As we know by poiseuille's equation of viscous flow of liquid through cylindrical pipe

Q = \frac{\Delta P \pi r^4}{8\eta L}

here we know that

L = 4 cm

\eta = 1 \times 10^{-3} Pa s

r = 1 mm

Q = flow rate

\pi r^2 v = \frac{\Delta P \pi r^4}{8\eta L}

v = \frac{\Delta P r^2}{8 \eta L}

10 = \frac{\Delta P (10^{-3})^2}{8(1 \times 10^[-3})(0.04)}

3.2 \times 10^{-3} = \Delta P (10^{-6})

\Delta P = 3.2 \times 10^3 Pa

now we have

P_p - P_{atm} = 3.2 \times 10^3

P_p = 1.01 \times 10^5 + 3.2 \times 10^3

P_p = 1.042 \times 10^5 Pa

8 0
3 years ago
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance
FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0
3 years ago
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