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Olegator [25]
3 years ago
8

While mowing your lawn, you push a lawnmower 120. m with a constant force of 300. N. How much work have you done, assuming that

all force is in the same direction as the direction of motion? Express your answer in scientific notation.
a)2.5 x 101 J
b)2.50 x 101 J
c)3.6 x 104 J
d)3.60 x 104 J
Physics
1 answer:
Montano1993 [528]3 years ago
3 0
We have: Work done = Force × Displacement
Here, Force = 300 N
Displacement = 120 m

Substitute their values into the formula:
W = 300 × 120 
W = 36000

In scientific notation, it would be: 3.6 × 10⁴

Finally, option C would be your correct answer.

Hope this helps!
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A sinusoidal transverse wave of amplitude ym = 8.4 cm and wavelength = 5.3 cm travels on a stretched cord. Find the ratio of the
Scilla [17]

Answer:

The ratio is 9.95

Solution:

As per the question:

Amplitude, y_{m} = 8.4\ cm

Wavelength, \lambda = 5.3\ cm

Now,

To calculate the ratio of the maximum particle speed to the speed of the wave:

For the maximum speed of the particle:

v_{m} = y_{m}\times \omega

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\omega = 2\pi f = angular speed of the particle

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v_{m} = 2\pi fy_{m}

Now,

The wave speed is given by:

v = f\lambda

Now,

The ratio is given by:

\frac{v_{m}}{v} = \frac{2\pi fy_{m}}{f\lambda}

\frac{v_{m}}{v} = \frac{2\pi \times 8.4}{5.3} = 9.95

8 0
4 years ago
Show all work.
lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

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F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

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brainly.com/question/12785992

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3 0
3 years ago
Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed
ANTONII [103]

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

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we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

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so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

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3 0
3 years ago
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avanturin [10]

Answer:

Explanation:

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DedPeter [7]

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Explanation:

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