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Ghella [55]
3 years ago
10

WILL MARK BRAINLEST

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

A

<em>Hope that helps!</em>

Step-by-step explanation:

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If f(x) = 4x – 5 and g(x) = 3 – 2x, find f(x) + g(x).
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(4x-5)+(2x-3)

4x+2x= 6x
-5+-3= -8

6x-8
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Step-by-step explanation:


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Step-by-step explanation:

s gm knfc JC. jz. jz. .xx nkcmxd I nt☺️️

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3 years ago
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The area of a rectangle is the rectangle’s length times its width. Write a program that asks for the length and width of two rec
Mnenie [13.5K]

Answer:

Using c++

Check the image for colors.

Step-by-step explanation:

#include <iostream>

using namespace std;

int main()

{

   float length1,length2,width1,width2,area1,area2;

   

   cout<<"length of Rectangle 1\n";

   cin>>length1;

   cout<<"\nwidth of Rectangle 1\n";

   cin>>width1;

   cout<<"\nlenght of Rectangle 2\n";

   cin>>length2;

   cout<<"\nwidth of Rectangle 2\n";

   cin>>width2;

   

   area1=length1*width1;

   area2=length2*width2;

   

   if (area1<area2)

   {cout << "\nRectangle 2 has greater area";}

   else {

               if (area1>area2)

                  {cout << "\nRectangle 1 has greater area";}

               else {cout << "\nAreas are the same";}

         }

   

   return 0;

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7 0
3 years ago
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

cos(t)=\sqrt{1-x^2}

Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

7 0
3 years ago
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