Look at picture for question. will mark brainilest PLEASE

Find the mean ( average):
105 + 104 + 110 + 112 + 114 + 106 + 108 +109 = 868
Mean = 868 / 8 = 108.5

Standard deviation:
108.5 - 105 = 3.5, 3.5^2 = 12.25
108.5 - 104 = 4, 4^2 = 16
110 - 108.5 = 1.5, 1.5^2 = 2.25
112 - 108.5 = 3.5, 3.5^2 = 12.25
114 - 108.5 = 5.5, 5.5^2 = 30.25
108.5 - 106 = 2.5, 2.5^2 = 6.25
108.5 - 108 = 0.5, 0.5^2 = 0.25
109 - 108.5 = 0.5, 0.5^2 = 0.25

12.25 + 16 +2.25 + 12.25 + 30.25 +6.25+0.25+0.25 = 79.75
79.75/8 = 9.96875, SQRT(9.96875) = 3.1573

Standard Deviation = 3.1573

108.8 +/- 1.96 *(3.1573/sqrt(8) = 110.687 and 106.312

110.687 - 108.5 = 2.19
108.5 - 106.312 = 2.19

Margin of error = +/- 2.19

3 0

2 years ago

The answer for my quiz

Levart [38]

PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong. PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right or wrong.

7 0

2 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$