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lord [1]
3 years ago
15

ANSWER PLEASEEE!!!20 points for the answer

Mathematics
2 answers:
Delvig [45]3 years ago
6 0

Answer:

A

Step-by-step explanation:

anygoal [31]3 years ago
5 0

Answer:

pretty sure its non- proportional. Sorry if in wrong!!!

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12 is 25% of what number
SashulF [63]
48? 12 times 4 is 48 and 1 part of 4 is 25%
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4 years ago
Choose the abbreviation of the postulate or theorem that supports the conclusion that the triangles are congruent.
Ber [7]

Answer:

Option D.

LA Theorem or Postulates

Explanation:

LA theorem or postulates is leg-acute states that if the leg and an acute angle of one right triangle are congruent to the corresponding leg and acute angle of another right triangle, then the triangles are congruent.

In \triangle ACB and  \triangle DFC

\angle C =\angle F = 90^{\circ}             [Given]

\angle B = \angle E   [Acute angle]      [Given]

BC=EF        [Given]

By LA theorems or postulates,

\triangle ACB \cong \triangle DFE

Therefore, LA theorems or postulates support the conclusion that the triangles are congruent.


     

8 0
3 years ago
Read 2 more answers
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
3 years ago
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Ur help is deeply appreciated! <3
andreev551 [17]
It’s C because something something (it had to be 20 characters long)
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Helppppppppppppppp please
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He is expected to earn 1.5 pts.
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