B).Proton acceptor did that help at all
I don't know sorry I wish I could help
debris from the volcanic ash has covered the sun which makes the temperature cold.
The change in internal energy that accompanies the transfer of heat (q) or work (w), into or out of a system can be calculated using the following equation: Note the value of heat and work as they are transferred into or out of a system.
Answer:
The specific heat of the mineral is 0.1272J/g°C
Explanation:
The sample is given energy to the calorimeter and the sample of water.
The energy released for the sample is equal to the energy absorbed for both the calorimeter and the water:
C(Sample)*m*ΔT = C(Calorimeter)*ΔT + C(water)*m*ΔT
<em>Where C is specific heat</em>
<em>m is mass of the sample and water</em>
<em>And ΔT is change in temperature</em>
<em />
C(Sample)*149g*(92.7°C-23.7°C) = 12.8J/K*(23.7°C-20.0°C) + 4.184J/g°C*81.4g*(23.7°C-20.0°C)
C(Sample)*10281g°C = 47.36J + 1260.1J
C(Sample) = 0.1272J/g°C
<h3>The specific heat of the mineral is 0.1272J/g°C</h3>
<em />