Answer:
3.4 × 10^23 molecules
Explanation:
To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).
number of molecules = number of moles (mol) × 6.02 × 10^23?
Number of molecules = 0.565 × 6.02 × 10^23
3.4 × 10^23 molecules
V1/T1 = V2/T2
V1= 3.5 L
T1 = 25 +273=298 K
T2 = 40.9 + 273 = 313.9 K
V2- ?
3.5 L/298 K= V2/ 313.9 K
V2 = (3.5 L*313.9 K)/298 K ≈ 3.69 L
4NH3+5O2 <=>4NO + 6H2O
Using the definition of Kp, we have
Kp=(Pno^4*Ph2o^6)/(Pnh3^4*Po2^5)
where Pno=partial pressure of NO, etc.
The numerical value for a given temperature can be evaluated when the actual partial pressures are known.