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3 years ago

Which best describes a swimming pool?

Chemistry

2 answers:

vesna_86 [32]3 years ago

6 0

Answer:

Swimming pool is an example of solution

Explanation:

It has water (solvent) and dissolve ion (solute)

almond37 [142]3 years ago

5 0

Answer:

it is a solution

Explanation:

the combining of (water and Cl and other pool chemicals) make it a solution.

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Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen.

mr_godi [17]

4Al + 3O₂ ----> 2Al₂O₃
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4 years ago

Which are correct ???

pav-90 [236]

Answer:

last one

Explanation:

endothermic reactions release energy

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3 years ago

Matthew and Bradley got into an argument. Matthew was convinced that the above picture was RNA, and Bradley was positive that it

Ber [7]

<span>the right answer is .C )<span>Matthew was right because RNA is single-stranded while DNA is double-stranded.</span></span>

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4 years ago

Read 2 more answers

What is the concentration of Sr2+ in a saturated solution of SrSO4? SrSO4 has a Ksp of 3.2 x 10–7

Nitella [24]

SrSO₄(s) ⇄ Sr²⁺(aq) + SO₄²⁻(aq)

Ksp=[Sr²⁺][SO₄²⁻]

[Sr²⁺]=[SO₄²⁻]

Ksp=[Sr²⁺]²

[Sr²⁺]=√Ksp

[Sr²⁺]=√3.2*10⁻⁷=5.66×10⁻⁴ mol/L

5 0

3 years ago

"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Alex17521 [72]

Answer:

$\boxed{\text{0.50 mol/L}}$

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

$\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}$

2. Solve for x

$K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}$

3. Calculate the equilibrium concentration of COF₂

c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

$\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}$

Check:

$\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}$

OK.

5 0

4 years ago