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Yuki888 [10]
3 years ago
10

Write an inequality that represents the situation below:

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

4 ( x - 2) > 5

Step-by-step explanation:

I think that's the right answer

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(8.75-2.16)÷7.1+(4.5+1.3)÷4.3
kirill [66]

Answer:

2.27700622339

Step-by-step explanation:

Calculated your welcome

7 0
3 years ago
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What is the measure of the largest angle on the triangle!
nalin [4]
Okay, so as you may know the inside angles of a triangle always add up to 180! so you must first find x, so that means add up all equations to find x. your answer is 41




























6 0
3 years ago
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Help please I’ve been here for a while...
lukranit [14]
B just trust me bro I got you
4 0
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One type of insect is 0.0052 meter long. What is this length in scientific notation?
____ [38]
Ok so...

You want to move the decimal point to the right until the number is greater than 1 but less than 10.

The number will end up being 5.2

You moved the decimal point 3 times to the right.
So it will be 5.2 x 10^-3. It is negative because you moved it to the right. The exponent would be positive if you moved it to the left

5 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
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