Give me 2 animals to combine their inherited traits

Physics

2 answers:

nydimaria [60]3 years ago

8 0

I think cats and dogs

Kazeer [188]3 years ago

7 0

Answer:

dogs and cats

Explanation:

hope this helps

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Giving 12 points for this question.

Ratling [72]

Fusion is the energy source of stars. The energy that is being released from the gas collapse into a protostar causes the center of the protostar to become extremely hot. Once the core is hot enough, nuclear fusion commences. The fusion reaction is a very structured process, releasing a huge amount of energy.

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3 years ago

Calculate the kinetic energy in joules of a 10g bullet moving at 300 m/s

mina [271]

Given: Mass m= 10 g convert to Kg m = 0.01 Kg Velocity V = 300 m/s

Required: Kinetic energy = K.E = 1/2 mV²

K.E = 1/2 (0.01 Kg)(300 m/s)²

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4 years ago

Read 2 more answers

Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts o

likoan [24]

Answer:

1) At the highest point of the building.

2) The same amount of energy.

3) The kinetic energy is the greatest.

4) Potential energy = 784.8[J]

5) True

Explanation:

Question 1

The moment when it has more potential energy is when the ball is at the highest point in the building, that is when the ball is at a height of 40 meters from the ground. It is taken as a point of reference of potential energy, the level of the soil, at this point of reference the potential energy is zero.

$E_{p} = m*g*h\\E_{p} = 2*9.81*40\\E_{p} = 784.8[J]$

Question 2)

The potential energy as the ball falls becomes kinetic energy, in order to be able to check this question we can calculate both energies with the input data.

$E_{p}=m*g*h\\ E_{p} = 2*9.81*20\\ E_{p} = 392.4[J]\\$

And the kinetic energy will be:

$E_{k}=0.5*m*v^{2}\\ where:\\v = velocity = 19.8[m/s]\\E_{k}=0.5*2*(19.8)^{2}\\ E_{k}=392.04[J]$

Therefore it is the ball has the same potential energy and kinetic energy as it is half way through its fall.

Question 3)

As the ball drops all potential energy is transformed into kinetic energy, therefore being close to the ground, the ball will have its maximum kinetic energy.

$E_{k}=E_{p}=m*g*h = 2*9.81*40\\ E_{k} = 784.8[J]\\ E_{k} = 0.5*2*(28)^{2}\\ E_{k} = 784 [J]$