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emmainna [20.7K]
3 years ago
14

Give me 2 animals to combine their inherited traits

Physics
2 answers:
nydimaria [60]3 years ago
8 0
I think cats and dogs
Kazeer [188]3 years ago
7 0

Answer:

dogs and cats

Explanation:

hope this helps

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Autorhythmic cells can generate action potentials spontaneously because they have Autorhythmic cells can generate action potenti
OlgaM077 [116]

Answer:

They can generate potentials spontaneously because they have Unstable Membrane Potentials.

Explanation:

Autorythmic cells or Pacemaker cells are cells that provide Action potentials (electrical impulses) that starts off the cardiac cycle.

N:B This action potential is created spontaneously.

To explain further, the heart originate in specialized cardiac muscle cells, called autorhythmic cells, that can excite themselves and therefore are able to generate an action potential without external stimulation by nerve cells. And this sets the cardiac cycle i

(Pumping of the heart) into motion. (The pace maker potential)

The Autorhythmic cells create an action potential spontaneously

And this is possible because they have an UNSTABLE RESTING POTENTIAL that is continuously depolarizing, while it drifts slowly toward threshold. As Na+ ions enter the cell, the inner surface of the plasma membrane becomes less negative gradually, thus generating the pacemaker potential.

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3 years ago
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3. Question
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2. Newton's laws of motion
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3 years ago
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Please Help! When a metal is heated, the free electrons gain _____________.
lakkis [162]
It’s B potential energy
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4 years ago
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Explain how an electrical wet cell functions.
Fynjy0 [20]
The chemical reaction causes electricity to flow through the terminals to the load attached. Some of the acid in the battery remains on the plates as it flows through. When the battery is recharged the acid is returned to the liquid solution to provide more power later.
3 0
3 years ago
Inserting the formulas you found for Xman(t) and Xbus(t) into the conditionXman(tcatch)=Xbus(tcatch) , you obtain the following-
lara [203]

Answer:

c > √(2ab)

Explanation:

In this exercise we are asked to find the condition for c in such a way that the results have been real

The given equation is

              ½ a t² - c t + b = 0

we can see that this is a quadratic equation whose solution is

             t = [c ±√(c² - 4 (½ a) b)]  / 2

for the results to be real, the square root must be real, so the radicand must be greater than zero

              c² -2a b > 0

              c > √(2ab)

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3 years ago
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