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Sergio039 [100]
4 years ago
15

A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the follow

ing conditions
Physics
2 answers:
insens350 [35]4 years ago
8 0

Answer:

hi your question lacks the options here is the complete question

A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the following conditions

(a) A currently licensed California Civil, Electrical, or Mechanical Engineer, as appropriate, is in charge of the engineering practice of the business.

(b) All engineering plans and specifications are prepared by an appropriately licensed engineer.

(c) The name and business contain only the name of the licensed engineer.

(d) None. No provisions exist.

Answer: B

Explanation:

Generally a non-licensed person is not allowed to be a sole owner of an engineering business because it requires engineering plans and specifications to be made and carried out hence a certified/licensed  Engineer alone can do that.

from the conditions given the only condition suitable for a non-licensed person to be the sole owner of an engineering business is that the engineering plans and specifications are prepared by an appropriately licensed engineer either working for the engineering business or contracted .

ra1l [238]4 years ago
4 0

Answer:

No.

Explanation:

The "guide to Engineering and land surveying" for professional engineers and land surveyors by the California board reviews that an unlicensed person cannot be a sole owner of an engineering business, unless there is partnership with a licensed engineer.

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[  Example:  Speed  =  (length) / (time)  ]

Density is not the mass of a substance.  It's the mass of a substance in
a standard volume of it.  So the density is made of the mass in any lump
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6 0
3 years ago
An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach
matrenka [14]

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, \theta=60^{\circ}

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m

So, the maximum height reached by the object is 34.43 m.

6 0
3 years ago
What are the benefits of physical exercises?
makvit [3.9K]

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Manage your weight

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7 0
3 years ago
Describe in your own words what is meant by the statement that the Sun is in hydrostatic equilibrium.
Jet001 [13]

Answer and Explanation:

Hydrostatic equilibrium is the condition in which force is balance that is upward force and downward force the downward force is due to gravitational force and the upward force is due to the pressure. The Sun is said to be in hydrostatic equilibrium means the force acting on it is balance means upward force which is due to pressure is same as the force exerted by gravitation.

8 0
4 years ago
As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s2 as it slows from 9.0 m/s
Dennis_Churaev [7]

Answer:

The time interval of acceleration for the bus is 2.20 seconds

Explanation:

Acceleration is the rate of change of velocity

→ a=\frac{v-u}{t}

where a is the acceleration, v is the final velocity, u is the initial velocity

and t is the time

The given is:

The uniform acceleration = -4.1 m/s²

The bus slows from 9 m/s to 0 m/s

We need to find the time interval of acceleration for the bus

Lets use the rule above

→ a = -4.1 m/s² , v = 0 m/s , u = 9 m/s

→ -4.1=\frac{0-9}{t}

Multiply both sides by t

→ -4.1 t = -9

Divide both sides by -4.1

∴ t = 2.20 seconds

<em>The time interval of acceleration for the bus is 2.20 seconds</em>

3 0
4 years ago
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