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Sergio039 [100]
3 years ago
15

A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the follow

ing conditions
Physics
2 answers:
insens350 [35]3 years ago
8 0

Answer:

hi your question lacks the options here is the complete question

A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the following conditions

(a) A currently licensed California Civil, Electrical, or Mechanical Engineer, as appropriate, is in charge of the engineering practice of the business.

(b) All engineering plans and specifications are prepared by an appropriately licensed engineer.

(c) The name and business contain only the name of the licensed engineer.

(d) None. No provisions exist.

Answer: B

Explanation:

Generally a non-licensed person is not allowed to be a sole owner of an engineering business because it requires engineering plans and specifications to be made and carried out hence a certified/licensed  Engineer alone can do that.

from the conditions given the only condition suitable for a non-licensed person to be the sole owner of an engineering business is that the engineering plans and specifications are prepared by an appropriately licensed engineer either working for the engineering business or contracted .

ra1l [238]3 years ago
4 0

Answer:

No.

Explanation:

The "guide to Engineering and land surveying" for professional engineers and land surveyors by the California board reviews that an unlicensed person cannot be a sole owner of an engineering business, unless there is partnership with a licensed engineer.

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A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre
pantera1 [17]

Answer:

Part a)

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

t = 12 s

Explanation:

Part a)

Tension in the rope at a distance x from the lower end is given as

T = \frac{m}{L}xg + Mg

so the speed of the wave at that position is given as

v = \sqrt{\frac{T}{\mu}}

here we know that

\mu = \frac{m}{L}

now we have

v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

time taken by the wave to reach the top is given as

t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}

t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})

t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})

t = 12 s

4 0
2 years ago
Help!!! Line B touches the circle at a single point. Line A extends through the center of the circle.
Ulleksa [173]

Answer:

If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.

  1. The size of the circle determines.
  2. The diameter should not be fixed either.
3 0
3 years ago
a ball moves at a constant speed of 1/2 meter per second. How much time does it take the ball to move 1 meter?
lesya [120]

Answer:

2 seconds

Explanation:

if a ball travels 1/2 meter per second, and there's 2 halfs in a whole, 1/2 meter per second x 2 halfs in a whole meter is 2 seconds to travel a meter

4 0
3 years ago
This problem follows up on a discussion from lecture. A wind turbine with an efficiency of 45% for converting wind energy into e
Volgvan

Answer:

4.1 m

Explanation:

10 kW = 10000 W

20mi/h = 20*1.6 km/mi = 32 km/h = 32 * 1000 (m/km) *(1/3600) hr/s = 8.89 m/s

The power yielded by the wind turbine can be calculated using the following formula

P = \frac{1}{2} \rho v^3 A C_p

where \rho = 1.2 kg/m^3 is the air density, v = 8.89 m/s is the wind speed, A is the swept area and C_p = 0.45 is the efficiency

10000 = 0.5 * 1.2 * 8.89^3 * A * 0.45

10000 = 190A

A = 10000 / 190 = 52.7 m^2

The swept area is a circle with radius r being the blade length

\pi r^2 = A = 52.7

r^2 = 52.7 / \pi = 16.79

r = \sqrt{16.79} = 4.1 m

4 0
2 years ago
A person has a gravitational force (weight) of 600 N on Earth. Suppose the mass of the Earth is double and the radius shrinks to
Alenkasestr [34]

Explanation:

that's impossible,the radius of the earth can't decrease when the mass doubles!

4 0
2 years ago
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