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Aleks [24]
3 years ago
9

The wavelengths of radio waves are much _______________ than the wavelength of microwaves. therefore, radio waves carry much ___

_______ energy than a microwave.
Physics
2 answers:
velikii [3]3 years ago
8 0

Answer:

The wavelengths of radio waves are much longer than the wavelength of microwaves. therefore, radio waves carry much lower energy than a microwave.

Explanation:

The wavelength of radio waves is longer than the wavelength of microwaves.

Using the equation that relates energy and wavelength:

E=\frac{hc}{\lambda}

where h and c are constants (h is Planck's constant and c the constant of the velocity of light)

And \lambda is the wavelength.

What this equation tells us is that the energy is inversely proportional to the wavelength. The larger the wavelength, the lower the energy that the wave carries.

So, since the wavelength of radio waves is much longer, its energy is much lower than the energy of microwaves.

nydimaria [60]3 years ago
7 0
The wavelengths of radio waves are much "Longer" than the wavelength of microwaves therefore, radio waves carry much "Lower" <span>energy than a microwave.

Hope this helps!</span>
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A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's
sergey [27]

Answer:

Time, t = 2 seconds

Explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

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To find the time, we would use the following formula;

F = \frac {m(v - u)}{t}

Making time, t the subject of formula, we have;

t = \frac {m(v - u)}{F}

Substituting into the formula, we have;

t = \frac {50(8 - 0)}{200}

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3 years ago
Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s
tatyana61 [14]

Answer:

Q_T=63313.5\ J

Explanation:

Given:

  • temperature of skin, T_s=34^{\circ}C
  • initial temperature of steam vapour, T_v=100^{\circ}C
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<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

where:

Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

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