Answer:
C. 1.35
Explanation:
2NH3 (g) <--> N2 (g) + 3H2 (g)
Initial concentration 2.2 mol/0.95L 1.1 mol/0.95L 0
change in concentration 2x x 3x
-0.84 M +0.42M +1.26M
Equilibrium 1.4 mol/0.95L=1.47M 1.58 M 1.26 M
concentration
Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M
Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M
Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M
K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M
Answer:
Explanation:
Hello,
In this case, for the given chemical reaction, the law of mass action at equilibrium results:
Next, in terms of the change due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:
Thus, solving for via quadratic equation or solver, the following results are obtained:
Clearly, the solution is as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:
Best regards.
Answer:
- <u><em>Option D. qsys = - qsurr</em></u>
Explanation:
The symbol q is used to denote heat energy.
Considering positive the heat absorbed and negative the heat released:
- <em>qsys</em> is the heat absorbed by the systme
- <em>qsurr</em> is the heat absorbed by the surroundings
When the system does not do work on or receive work from the surroundings, the first law of thermodynamics states that:
- <em>qsys </em>+ <em>qsurr</em> = 0
From which:
- <em>qsys = - qsurr ← </em>answer
That is the option D.
That means that, the heat abosorbed by the system (if <em>qsys</em> is positive) equals the heat released by the surroundings, or the heat released by the system (if <em>qsys</em> is negative) equals the heat absorbed by the surroundings.
No because it has less gravity and there is nothing that can run forever eventually the strings will wear out or the balls would stop
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