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stepan [7]
3 years ago
8

The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities f

or and are 1.6 and 2.1 respectively. Calculate the fraction of the bonding that is ionic.
Chemistry
1 answer:
9966 [12]3 years ago
3 0

Answer:

0.08875

Explanation:

Hello,

In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:

\Delta E=2.1-1.6\\\\\Delta E=0.5

Thus, we can compute the percentage of ionic character by:

\%\  ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\  ionic\ character=16*0.5+3.5*0.5^2\\\\\%\  ionic\ character=8.875\%

So the fraction is just:

\frac{8.875}{100}=0.08875

Which has sense since gallium phosphide is a non-polar compound.

Regards.

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5 0
3 years ago
The intensity of illumination at any point from a light source is proportional to the square of the reciprocal of the distance b
SSSSS [86.1K]

Answer:

the stronger light 5.5 m apart from the total illumination​

Explanation:

From the problem's statement , the following equation can be deducted:

I= k/r²

where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality

denoting 1 as the stronger light and 2 as the weaker light

I₁= k/r₁²

I₂= k/r₂²

dividing both equations

I₂/I₁ = r₁²/r₂²=(r₁/r₂)²

solving for r₁

r₁ = r₂ * √(I₂/I₁)

since we are on the line between the two light​ sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus

r₂ = r₁ + d

then

r₁ = (r₁ + d)* √(I₂/I₁)

r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)

r₁*(1-√(I₂/I₁)) =  d*√(I₂/I₁)

r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁))  =

r₁ = d/[√(I₁/I₂)-1)]

since the stronger light is 9 times more intense than the weaker

I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3

then since d=11 m

r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m

r₁ = 5.5 m

therefore the stronger light 5.5 m apart from the total illumination​

5 0
3 years ago
When calcium and chlorine react to form calcium chloride, which substance is reduced? *
zhannawk [14.2K]

<u>Answer</u>:-

When the reaction takes place Ca is reduced or is an oxidizing agent.

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Ca + 2Cl =CaCl2

Note: There is a +2 charge on Ca(Calcium) and -1 charge on each Cl-atom(Chlorine atom) hence the charges are cancelled. Therefore, the total charge on the whole compound is zero.

Explanation:-

• Reduction: gain of electron/electrons

gain of hydrogen

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Oxidation: gain of oxygen

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loss of electron/electrons.

• Oxidizing agent/reduced

Reducing agent/oxidized

• The molecule that is oxidized loses an electron and the molecule that is reduced gains the electron that was lost by the oxidized molecule.

6 0
3 years ago
Read 2 more answers
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