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DENIUS [597]
3 years ago
6

Which mathematical statement correctly relates qsys and qsurr? A. qsys = qsurr B. qsys < qsurr C. qsys > –qsurr D. qsys =

–qsurr
Chemistry
1 answer:
tatiyna3 years ago
4 0

Answer:

  • <u><em>Option D. qsys = - qsurr</em></u>

Explanation:

The symbol q is used to denote heat energy.

Considering positive the heat absorbed and negative the heat released:

  • <em>qsys</em> is the heat absorbed by the systme

  • <em>qsurr</em> is the heat absorbed by the surroundings

When the system does not do work on or receive work from the surroundings, the first law of thermodynamics states that:

  • <em>qsys </em>+ <em>qsurr</em> = 0

From which:

  • <em>qsys = - qsurr ← </em>answer

That is the option D.

That means that, the heat abosorbed by the system (if <em>qsys</em> is positive) equals the heat released by the surroundings, or the heat released by the system (if <em>qsys</em> is negative) equals the heat absorbed by the surroundings.

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The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?
n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of atmosphere = 5.00\times 10^{18}kg=5.00\times 10^{21}g

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = \frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol

Moles of carbon dioxide in air = \frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol

Hence, the moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

6 0
3 years ago
A sample of gas consists of 4.0 moles, and exists at stp. What is the volume of the gas?
faust18 [17]

Answer:

The volume of the gas is 89.60

Explanation:

When converting from moles to volume, you would multiply by 22.4 because 1 mole equals 22.4 liters at STP.

So...

4.0 moles * 22.4 liters =

89.60 liters

6 0
2 years ago
Read 2 more answers
What coefficient of h+ balances the atoms in this half-reaction h+ + mno2 → mn2+ + h2o?
kvv77 [185]
The answer is 4 im pretty sure 
7 0
3 years ago
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An astronaut in her spacesuit weighs 300 lb on earth. What would her weight be on the moon?
Phantasy [73]
She would be 150 on the moon because the moon has half the mass of earth
6 0
3 years ago
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A stock solution has a concentration of 1.5 M NaCl and is diluted to a 0.80 M solution with a volume of 0.10 L. What volume of t
ioda

Answer:

0.053 L  is the volume of concentrated solution that was used

Explanation:

Let's determine the answer of this, by rules of three.

There is also a dilution formula.

Molarity is a sort of concentration that indicates the moles of solute in 1L of solution.

In 1 L of concentrated solution, there are 1.5 moles of NaCl

In 1 L of diluted solution, there are 0.80 moles.

The volume for the diluted solution is 0.10L

The rule of three will be:

1L of solution has 0.80 moles of solute

Then, 0.10L of solution must have (0.1 . 0.8)/1 = 0.08 moles

This moles came from the concentrated solution, and we know that in 1L of this solution we have 1.5 moles. Therefore the rule of three will be:

1.5 moles are in 1L of solution

0.08 moles were in (0.08 . 1L / 1.5) = 0.053 L (This is the volume of concentrated solution that was used)

Dilution formula is: M conc . Vol conc = M diluted . Vol diluted

1.5 M . Vol conc = 0.80 M . 0.10L

Vol conc = 0.80 M . 0.10L / 1.5M = 0.053L

4 0
3 years ago
Read 2 more answers
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