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2 years ago

Please help i am stuck

Mathematics

1 answer:

irinina [24]2 years ago

3 0

Answer:

it's to be able to add them

Step-by-step explanation:

for example like it shows in the picture,

it wont be easy to add 1/2 and 2/3

so, you unsimplify them to 3/6 and 4/6 so you just add the numerators and the demoninator stays the same

You might be interested in

The sum of two consecutive even integers is 106. What are the integers?

Kruka [31]

Answer:

The integers are 52 and 54

Step-by-step explanation:

x = first even integer

x + 2 = next integer that is even

x + x + 2 = 106

2x + 2 = 106

2x = 104

x = 52

x + 2 = 54

4 0

1 year ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

Please help is needed urgently! 8th grade math question?!

AURORKA [14]

ratio of the diagonal to the side of the rectangle is 17/8 or 17:8

Step-by-step explanation:

Length of Diagonal = 34 inches

Length of side = 16 inches

Base= 30 inches

We need to find the ratio of the diagonal to the side of the rectangle.

ratio of the diagonal to the side of the rectangle = $\frac{length of diagonal}{length of side}$

Putting values:

$Ratio=\frac{34}{16} \\Simplifying:\\Ratio=\frac{17}{8}$

So, ratio of the diagonal to the side of the rectangle is 17/8 or 17:8

Keywords: ratio

Learn more about ratio at:

#learnwithBrainly

6 0

3 years ago

Tell whether the rates form a proportion.

pav-90 [236]

Answer: no

Step-by-step explanation: the answer is no

5 0

2 years ago

If f(x)=x^2 + 8x find f(d-3)

pogonyaev

F(x)=x^2 +8x
f(d-3) basically what we get from this is that the x value is d-3
to find f(d-3) simply plug in d-3 for every x
f(d-3)=(d-3)^2 + 8(d-3)
that would be one form of the answer, but we can also continue multiplying it out
f(d-3)= d^2-6d+9+8d-24
add like terms
f(d-3)=d^2+2d-15

have a nice day and i hope this helps :)

7 0

2 years ago