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oksano4ka [1.4K]
3 years ago
7

Please help i am stuck

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

it's to be able to add them

Step-by-step explanation:

for example like it shows in the picture,

it wont be easy to add 1/2 and 2/3

so, you unsimplify them to 3/6 and 4/6 so you just add the numerators and the demoninator stays the same

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Answer:

B. \frac{4x^{2}+24x+31}{3x^{2}+13x+12}

Step-by-step explanation:

We have been given a rational expression \frac{(x+5)}{(3x+4)}+\frac{(x+4)}{(x+3)} and we are asked to simplify our rational expression.

We can see that our denominators are not equal. Since the two denominators do not share any common factors, the common denominator is simply the product of these two denominators.      

To keep the value of expression same we will multiply the same quantity with numerators and denominators.

\frac{(x+5)(x+3)}{(3x+4)(x+3)}+\frac{(x+4)(3x+4)}{(x+3)(3x+4)}  

Now let us simplify our expression using FOIL.  

\frac{x^{2}+3x+5x+15}{3x^{2}+9x+4x+12}+\frac{3x^2+4x+12x+16}{3x^{2}+4x+9x+12}

\frac{x^{2}+8x+15}{3x^{2}+13x+12}+\frac{3x^2+16x+16}{3x^{2}+13x+12}    

Now we have same denominators, so we can add our numerators.

\frac{x^{2}+8x+15+3x^2+16x+16}{3x^{2}+13x+12}    

Now let us combine like terms.

\frac{(1+3)x^{2}+(8+16)x+15+16}{3x^{2}+13x+12}  

\frac{4x^{2}+24x+31}{3x^{2}+13x+12}  

Therefore, the simplest form of our given rational expression will be \frac{4x^{2}+24x+31}{3x^{2}+13x+12}  and option B is the correct choice.

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