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marshall27 [118]
4 years ago
5

What mass of sulfur must burn to produce 3.42 L of So2 at STP

Chemistry
1 answer:
beks73 [17]4 years ago
7 0
Number of moles SO2 :

1 mol SO2 -------- 22.4 L ( at STP )
? mol SO2 --------- 3.42 L

1 x 3.42 / 22.4 => 0.152 moles of  SO2

Therefore:

Molar mass SO2 => <span>64.066 g/mol
</span>
1 mole SO2 ---------- <span>64.066 g
</span>0.152 moles SO2 ---- ( Mass of SO2)

Mass of SO2 = 0.152 x 64.066 / 1

Mass of SO2 = 9.738 g 


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I really need help with this problem.
Aleksandr [31]

Answer:

.371 mole of NaCl

Explanation:

Na Cl Mole weight = 22.989   + 35.45 = 58.439 g/mole

21.7 g / 58.439 g/mole = .371 mole

8 0
2 years ago
Compare and contrast: element, atom, isotope
blsea [12.9K]

Answer:

Element is made up of the atoms or isotopes. Isotopes are where only neutrons change in number, such as 3 turning to 2 or to 5. Atom is where it is not changed and it is the original, and example is instead of Carbon13 it is just Carbon. I hope this helps.

7 0
4 years ago
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Which element has 3 valence electrons in the 4d sublevel?<br><br> A. V<br> B. Nb<br> C. Cu<br> D. Tl
Lilit [14]
Nb, the transition metal(d) subshell will always be n-1, meaning the 3d subshell will be in row(period) 4. So if it’s 4d then it is row(period) 5, and if it has 3 valence electrons then the element is located in column V, or the third column in the transition metal section.
7 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everythi
zimovet [89]

Answer:

a) 79.66 seconds is the half-life of the reaction.

b) It will take 4.776\times 10^1 seconds for 34% of a sample of an acetone to decompose.

c) It will take 2.537\times 10^2 seconds for 89% of a sample of an acetone to decompose.

Explanation:

The decomposition of acetone follows first order kinetics

The rate constant of the reaction = k = 8.7\times 10^{-3} s^{-1}

a)

Half life of the reaction = t_{1/2}

For the first order kinetic half life is related to k by :

t_{1/2}=\frac{0.693}{k}

t_{1/2}=\frac{0.693}{8.7\times 10^{-3} s^{-1}}=79.66 s=7.966\times 10^1 s

79.66 seconds is the half-life of the reaction.

b)

Let the initial concentration of acetone be = [A_o]

Final concentration of acetone left after t time = [A]

A=(100\%-34\%)[A_o]=66\%[A_o]=0.66[A_o]

For the first order kinetic :

[A]=[A_o]\times e^{-kt}

0.66[A_o]=[A_o]\times e^{-8.7\times 10^{-3} s^{-1}\times t}

Solving for t;

t=47.76 s

It will take 47.76 seconds for 34% of a sample of an acetone to decompose.

c)

Let the initial concentration of acetone be = [A_o]

Final concentration of acetone left after t time = [A]

A=(100\%-89\%)[A-o]=11\%[A_o]=0.11[A_o]

For the first order kinetic :

[A]=[A_o]\times e^{-kt}

0.11[A_o]=[A_o]\times e^{-8.7\times 10^{-3} s^{-1}\times t}

Solving for t;

t=2.537\times 10^2 s

It will take 2.537\times 10^2 seconds for 89% of a sample of an acetone to decompose.

3 0
3 years ago
AUG, the codon that codes for the amino acid methionine is also called a ____ codon (answer choices 1.start 2.Stop 3.Go 4.beginn
Katarina [22]
<h2>Answer:  START (2)</h2>

Explanation:

AUG is a <u>START</u> codon.  (2)

A start codon is the first codon translated by a ribosome. It usually produces an amino acid that initiates the producyion of a polypeptide chain.

5 0
3 years ago
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