Answer:
a. -0.63 V
b. No
Explanation:
Step 1: Given data
- Standard reduction potential of the anode (E°red): -1.33 V
- Minimum standard cell potential (E°cell): 0.70 V
Step 2: Calculate the required standard reduction potential of the cathode
The galvanic cell must provide at least 0.70V of electrical power, that is:
E°cell > 0.70 V [1]
We can calculate the standard reduction potential of the cathode (E°cat) using the following expression.
E°cell = E°cat - E°an [2]
If we combine [1] and [2], we get,
E°cat - E°an > 0.70 V
E°cat > 0.70 V + E°an
E°cat > 0.70 V + (-1.33 V)
E°cat > -0.63 V
The minimum E°cat is -0.63 V and there is no maximum E°cat.
Answer: The boiling point of a 3.70 m solution of phenol in benzene is 
Explanation:
Elevation in boiling point:

where,
= change in boiling point
i= vant hoff factor = 1 (for benzene which is a non electrolyte )
= boiling point constant = 
m = molality = 3.70



Thus the boiling point of a 3.70 m solution of phenol in benzene is 
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Answer:</h2>

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London Dispersion force or Van de waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.
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Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.
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It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.
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Answer:
Beryllium-9 is the isotope of beryllium with relative atomic mass 9.
The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.
There are several ways to denote the concentration of a solution like
- Molarity
- Molality
- Mass percent
- Mole Fraction
The formula for calculating mass percent is as follows
Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%
In the given situation sugar is the solute and water is the solvent.
Putting the given values in the above formula
Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%
Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.
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