Answer:
I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.
n = 5 4th excited state
n = 4 3rd excited state
n = 3 2nd excited state
n = 2 1st excited state
n = 1 ground state
Here are the possible spectral lines.
n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.
n = 4 to 3, 4 to 2, 4 to 1 = 3 lines
n = 3 to 2, 3 to 1 = 2 lines
n = 2 to 1 = 1 line. Add 'em up. I get 10.
b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.
c.The E for any level is -21.8E-19 Joules/n^2
To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.
So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.
Explanation:
Like in general, or is there something u didn't put?<span />
Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.
Recalling the principle:
initial volume x initial molarity = final volume x final molarity
Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:
Applying the dilution principle:
10 x 20 = final volume x 15
final volume = 200/15
= 13.33 mL
This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.
More on dilution principle can be found here: brainly.com/question/11493179
Answer:
29.92grams of PbSO4
Explanation:
lead (iV) oxide = PbO2 = Molar mass: 239.2 g/mol
lead (ll) sulfate = PbSO4 = Molar mass: 303.26 g/mol
PbO2 = PbSO4
1:1 ratio
Pb = Lead
Lead has an oxidation number of 4+
O = Oxygen
Oxygen has an oxidation number of 2-
PbO2 + 4H+ + SO4 2- + 2e- = PbSO4(s) + 2H2O
Ok so the above would be the likely complete reaction, though we don't really need this as we already know the ratio is 1:1.
23.6g of PbO2
23.6/239.2 = 0.09866 Moles of PbO2
Since we have a 1:1 ratio we know that the same number of moles of PbSO4 are produced and since we know the molar mass it's simply molar mass multiplied by number of moles.
303.26 x 0.09866 = 29.92grams of PbSO4
Answer:
Hercules beetles, Dynastes hercules, occur in the new world tropics of Central and South America.
Explanation:
The southern Mexican border to west central Bolivia represent the species' northern and southern limitations, respectively.
