Decrease £19064.67 by 9.5% Give your answer rounded to 2 DP.
1 answer:
Answer:
New amount (decrease) = £17253.53
Step-by-step explanation:
<u>Given the following data;</u>
Amount = £19064.67
Percentage = 9.5%
To find the percentage decrease;
Percentage cost = £1811.14
New amount (decrease) = Original amount - percentage cost
Substituting into the equation, we have;
New amount (decrease) = £19064.67 - £1811.14
<em>New amount (decrease) = £17253.53</em>
You might be interested in
Answer:
option A and B
and
Step-by-step explanation:
we have
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
so
and
Answer:
1) There are 100 carbon-14 atoms in the wood when it died
2) A function that models the number 'N' of carbon-14 atoms present in the wood (t) years after it died is presented as follows;
Step-by-step explanation:
The given parameters are;
The number of carbon-12 for each carbon-14 atom ≈ 10¹² carbon-12 atoms
The number of carbon-12 in the piece of wood = 10¹⁴ carbon-12 atoms
The number of carbon-14 in the piece of wood = 40 carbon-14 atoms
The number of carbon-12 in an organism = Constant
The number of carbon-14 in an organism = Decays
1) Given that the number of carbon-12 in an organism is constant, and there are 10¹² carbon-12 atoms per each carbon-14 atom, therefore, we have;
The number of carbon-12 atoms in the wood when it died = 10¹⁴ carbon-12 atoms
The number of carbon-14 atoms in the wood when it died = (10¹⁴ carbon-12 atoms)/(10¹² carbon-12 atoms/(carbon-14 atom)) = 100 carbon-14 atoms
The number of carbon-14 atoms in the wood when it died = 100 carbon-14 atoms
2) The half life of a radioactive isotope is given by the following formula;
The half life of carbon-14 atoms, ≈ 5,730 years
N₀ = The amount of carbon-14 present in the wood when it died = 100 carbon-14 atoms
Therefore, we have;
The number, N, of carbon-14 atoms present in the wood (t) years after it died is given as follows;