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3 years ago

What percent of 41 is 27.9

Mathematics

2 answers:

SpyIntel [72]3 years ago

7 0

Answer:

Percentage: 27.9 is what percent of 41? = 68.048780487805 but I quess just put the answer as 69

Step-by-step explanation:

Hope this helps :)

Shalnov [3]3 years ago

6 0

Answer:

68.048780487805

Step-by-step explanation:

or just 68.04 or just 68

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Oksanka [162]

Answer:

1) 0

2) 0

3) 0

Explanation:

6 0

3 years ago

A company charges $85 per hour for jet ski rentals plus $7 per hour for fuel. Their competition charges $84 per hour plus a flat

loris [4]

85x + 7x= 84x + 40

Simplified further

92x = 84x + 40

7 0

3 years ago

Read 2 more answers

A university knows from historical data that 25% of students in an introductory statistics class withdraw before completing the

Vikki [24]

Answer:

13.4%

Step-by-step explanation:

Use binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, n = 16, r = 2, p = 0.25, and q = 0.75.

P = ₁₆C₂ (0.25)² (0.75)¹⁶⁻²

P = 120 (0.25)² (0.75)¹⁴

P = 0.134

There is a 13.4% probability that exactly 2 students will withdraw.

8 0

3 years ago

Round 4.2258..hours to the nearest minutes

RoseWind [281]

Answer:

253.548 minutes which rounds to 254 minutes

Step-by-step explanation:

1 hour = 60 minutes

4.2258 × 60 minutes = number of minutes per 4.2258 hours

253.548 minutes

The question does not specify how to round it so I will round to the nearest whole number: 254 minutes.

4 0

3 years ago

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

Dominik [7]

Answer:

Norma performed best on the aptitude test and should be offered the job.

Step-by-step explanation:

We are given that three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below. Tobias got a score of 74.7; this version has a mean of 61.7 and a standard deviation of 13. Norma got a score of 351; this version has a mean of 291 and a standard deviation of 25. Vincent got a score of 7.38; this version has a mean of 6.9 and a standard deviation of 0.4.

Now, to find which of the applicants should be offered the job, we have to find the z-score of each of the applicants, and the one who gets the highest z-score will get the job.

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean and $\sigma$ = standard deviation

Firstly, we will find the z-score for Tobias;

The z-score of 74.7 = $\frac{X-\mu}{\sigma}$

= $\frac{74.7-61.7}{13}$ = 1

Now, we will find the z-score for Norma;

The z-score of 351 = $\frac{X-\mu}{\sigma}$

= $\frac{351-291}{25}$ = 2.4

Now, we will find the z-score for Vincent;

The z-score of 7.38 = $\frac{X-\mu}{\sigma}$

= $\frac{7.38-6.9}{0.4}$ = 1.2

As we can clearly see that the z-score is highest for Norma which means that Norma performed best on the aptitude test and should be offered the job.

8 0

3 years ago