THIS IS URGENT !!!

A hollow cylindrical (inner radius = 1.0 mm, outer radius = 3.0 mm) conductor carries a current of 80 A parallel to its axis. Th

Pavlova-9 [17]

Answer:

The magnetic field is $B = 3 mT$

Explanation:

From the question we are told that

The inner radius is $r_i = 1.00 mm =1*10^{-3} \ m$

The outer radius is $r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m$

The distance from the axis of the conductor is $d =2.0 \ mm = 2.0 *10^{-3} \ m$

The current carried by the conductor is $I = 80 A$

According to Ampere's circuital law , the magnetic field at a point that is $r_3$ from the axis of the conductor

$B = \frac{\mu_oI}{2 \pi d } [\frac{d - r_1}{r_2 -r_1} ]$

Where $\mu_o$ is the permeability of free space with a value of $\mu_o = 4 \pi *10^{-7} N/A^2$

substituting values

$B = \frac{(4 \pi *10^{-7})(80)}{2 * 3.142 * 2 *10^{=3} } [\frac{(2^2 - 1 ^2 )*10^{-3}}{(3^2 - 1^2) *10^{-3}} ]$

$B = 3 mT$

5 0

4 years ago

Which energy resources are found above the Earth's surface

never [62]

Answer: the sun

Explanation:

The sun's radiant energy reaches the earth's surface either directly through radiation, indirectly through convection, or it can move "across" or "through" objects or materials on the surface via conduction. Let's look more closely at each case. We've probably experienced the feeling of "warmth" of the sun on our skin on a sunny day. Light energy from the sun is reaching us across space and down through the atmosphere through radiation. A dark colored vehicle in the sun quickly becomes warm (or hot!) to the touch because of radiation. The light energy from the sun heats the air in the earth's atmosphere, and this drives convection and transfers thermal energy around. It is possible that we've felt a "hot breeze" on our skin on sunny days. The thermal energy in the air will be carried to objects in its path, and it will warm them.

6 0

4 years ago

A 1.50 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

Tema [17]

Answer:

α = 1.114 × 10⁻³ (°C)⁻¹

Explanation:

Given that:

Length of rod (L) = 1.5 m,

Diameter (d) = 0.55 cm,

Area (A) = $\pi r^2$

Radius (r) = d / 2 = 0.275 cm,

Voltage across the rod (V) = 15.0 V.

At initial temperature (T₀) = 20°C, the current (I₀) = 18.8 A while at a temperature (T) = 92⁰C, the current (I) = 17.4 A

a) The resistance of the rod (R) is given as:

$R=\frac{Voltage(V)}{I_0} \\R=\frac{15}{18.8}=0.798\Omega$

Therefore the resistivity and for the material of the rod at 20 °C (ρ) is:

$\rho=\frac{RA}{L}=\frac{0.798*\pi *0.275^2}{1.5}=0.126\Omega m$

b) The temperature coefficient of resistivity at 20°C for the material of the rod (α) can be gotten from the equation:

$R_T=R_0[1-\alpha (T-T_0)]\\but,R_T=\frac{V}{I}=\frac{15}{17.4}=0.862\\$

Rearranging to make α the subject of formula:

$\frac{R_T}{R_0} =1+\alpha (T-T_0)\\\alpha (T-T_0)=\frac{R_T}{R_0}-1\\\alpha =\frac{\frac{R_T}{R_0}-1}{(T-T_0)} \\Substituting:\\\alpha =\frac{\frac{0.862}{0.798}-1 }{92-20} \\\alpha =\frac{0.0802}{72} =1.114*10^-3(^0C)^{-1$

8 0

3 years ago

baseball player hits a line drive estimated to have traveled 145 meters the ball leaves the bat with a horizontal velocity of 40

Amanda [17]

Answer:

5800

Explanation:

caluculatior

8 0

3 years ago

State and apply the relation between electric force and electric field.

Olin [163]

Answer:

The following is the relation between electric force and field

$Electric Field = Electric Force / charge$

Explanation:

Electric force is the magnitude of electrostatic forces between two charges which is directly proportional to product of both charges and inversely proportional to the square of the distance between them.

$F=k*q1*q2/r^2$

Here k is the coulumb's constant.

Where as the electric field is the electric force per unit charge. It is the function of electric force. It is the vector quantity and its direction is taken radially inward or outward depending on the nature of charge.

Its equation is

Electric Field $E=F/q$

Electric Field units are in volts where as Electric force units are newtons.

5 0

4 years ago