Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>
Where "r" is the radius
Thus the distance of a spin of one full rotation is 31.4 feet
I don't know what numbers you want me to order from great to least, but a example is 1,510, 964, 478, 219, 96, 57, 35, 10, 9, 4, 3,