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Tema [17]
3 years ago
12

The unknown measures of one triangle are about . The unknown measures of the other triangle are about .

Mathematics
2 answers:
Andrew [12]3 years ago
6 0

Answer:

The answer is "25 in"

Step-by-step explanation:

Please find the complete question in the attached file:

Given:

\to AB= 7 \ in \\\\\to  BC= 24 \ in \\\\ \to AC=?

Using the Pythagorean theorem:

\to AC^2=AB^2+BC^2\\\\

\to AC^2=7^2+24^2\\\\\to AC^2=49+576\\\\\to AC^2=625\\\\\to AC= 25\\

Liula [17]3 years ago
4 0

Answer:

The unknown measures of one triangle are about

✔ A = 103°, B = 42°, a = 27.4.

The unknown measures of the other triangle are about

✔ A = 7°, B = 138°, a = 3.4.

Step-by-step explanation:

copy / pasted from edge, if not correct lmk!!!

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Joseph's parents have planted two gardens. One is square and has an area of 25 ft 2. The other one has two sides equal to 2/3 of
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Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor
agasfer [191]

Answer:

  • E = { (4,1) , (3,2) , (2,3) , (1,4) }
  • P(E)=\frac{1}{9}
  • P(F|E)=\frac{1}{4}

Step-by-step explanation:

Let's start writing the sample space for this experiment :

S= { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event E ⇒

E : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from S ⇒

E = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate P(E) we are going to divide all the cases favorables to E over the total cases from S. We can do this because all 36 of these possible outcomes from S are equally likely. ⇒

P(E)=\frac{4}{36}=\frac{1}{9} ⇒

P(E)=\frac{1}{9}

Finally we are going to define the event F ⇒

F : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

F = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = P(A,B)

We define the conditional probability as

P(A|B)=\frac{P(A,B)}{P(B)} with P(B)>0

We need to find P(F|E) therefore we can apply the conditional probability equation :

P(F|E)=\frac{P(F,E)}{P(E)}   (I)

We calculate P(E)=\frac{1}{9} at the beginning of the question. We only need P(F,E).

Looking at the sets E and F we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

P(F,E)=\frac{1}{36}

Replacing both probabilities calculated in (I) :

P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25

We find out that P(F|E)=\frac{1}{4}=0.25

6 0
3 years ago
Linda owns 4 shares of a certain stock. Yesterday the total value of her shares went down by 32 dollars. What was the change in
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Answer:

The value of each share decreased by $8.

Step-by-step explanation:

Number of shares of a certain stock Linda owned = 4

Total value of shares went down by = $32

So find the change in value of each share.

Solution:

Let the total value of each share in dollars be = x

Value of 4 shares in dollars will be = 4x

The total value of shares went down by $32

So, new value of 4 shares = 4x-32

New value of each share = \frac{New\ value\ of\ total\ shares}{4}

⇒ \frac{4x-32}{4}

Splitting the denominators.

⇒ \frac{4x{{4}-\frac{32}}{4}

⇒ x-8

Original value of each share in dollars was = x

New value of each share in dollars = x-8

Thus, we can see that the value of each share decreased by $8.

6 0
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