Delta energy on labelled diagram is attached below
I think the answer is 1s²2s²2p⁶. Since neon has an atomic number of 10, we know that it needs to have 10 electrons and since it is in the second row it cannot have any d electrons which makes the first option incorrect. The second option is incorrect because the 2s⁴ can't exist since s orbitals can only hold 2 electrons. The fourth option cannot be right because it again neon cannot have d electrons due to it being in the second row.
I hope this helps. Let me know if anything is unclear.
The solution for the question above is:
C = 0.270
<span>V = 0.0275L </span>
<span>n = ? </span>
<span>Use the molar formula which is: C = n/V </span>
<span>Re-arrange it to: n = CV </span>
<span>n = (0.270)*(0.0275) </span>
<span>n = 0.007425 mols </span>
<span>(more precise) n = 7.425 x 10^-3 mols
</span>
7.425 x 10^-3 mols is the answer.
I think the answer is C. Hope this helped.
<u>We are given:</u>
P1 = 3 atm T1 = 623 K <em>(350 + 273)</em>
P2 = x atm T2 = 523 K <em>(250 + 273)</em>
<em />
<u>Solving for x:</u>
From the idea gas equation:
PV = nRT
since number of moles (n) , Volume (V) and the Universal Gas constant(R) are constants;
P / T = k (where k is a constant)
the value of k will be the same for a gas with variable pressure and temperature and constant moles and volume
Hence, we can say that:
P1 / T1 = P2 / T2
3 / 623 = x / 523
x = 523 * 3 / 623
x = 2.5 atm (approx)
Therefore, the final pressure is 2.5 atm
