Explanation:
when there is an increase in thermal energy, the kinetic energy if the matter increases as well.
given that acceleration due to gravity is g = 10 m/s^2
speed of the rocket will reach to 0.9c
now by kinematics
Part b)
distance traveled by it in above time
so this is the distance covered by the object
Answer:
Vf = 60 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vi = initial velocity = 0
a = acceleration = 1 [m/s^2]
t = time = 60 [m]
Now replacing:
Vf = 0 + (1*60)
Vf = 60 [m/s]
<u>We are given:</u>
the initial height of the object (h) = 100 m
initial velocity (u) = 0 m/s
we will let the value of g = 10 m/s/s
<u>Speed of the object just before hitting the ground:</u>
From the third equation of motion:
v² - u² = 2ah (where v is the final velocity)
replacing the variables, we get:
v² - (0)² = 2(10)(100)
v² = 2000
v = 10√20 = 44.7 m/s
Therefore, the speed of the object just before hitting the ground is 44.7 m/s
Answer: 7.8×10^5 J
Explanation:
Total energy = kinetic energy of plane + gravitational potential energy of plane.
Total energy = ((1/2)×m×v²) + (m×g×h)
Here, m is mass of plane, v is velocity of plane, g is acceleration due to gravity and h is height above the ocean.
Now,
Total energy = ((1/2)×m×v²) + (m×g×h)
Total energy = m((v²/2) + (g×h))
Total energy = 850((38²/2) + (9.81×20))
Total energy = 850(722 + 196.2)
Total energy = 7.8×10^5 J
